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Nina [5.8K]
2 years ago
6

Explain why cuboidal cells would not work as well as squamous cells in the alveoli of the lungs

Biology
2 answers:
guajiro [1.7K]2 years ago
8 0
The surfactant is produced by great alveolar cells (granular pneumonocytes, a cuboidal epithelia), which are the most numerous cells in the alveoli, yet do not cover as much surface area as the squamous alveolar cells (a squamous epithelium<span>).

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!



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valkas [14]2 years ago
6 0

Answer:

Cuboidal cells are thicker than squamous cells. Cuboidal cells are usually where a function of absorption or secretion is need.

Squamous cells are usually laid in a single layer making the layer thin. This is useful because this type of arrangement allows for diffusion to happen and its used where diffusion is the main type of transport. Remember that the rate of diffusion slows down with distance. In the lungs gas exchange needs to happen very fast to keep a constant supply of oxygen to the lungs. Cuboidal cells would be too thick.

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Your job is to write out a story about the Tissue Family Reunion which includes the following family members: epithelial, connec
marin [14]

Answer: Write out a story about the Tissue Family Reunion which includes the following family members: epithelial, connective, nervous, muscular. All of the tissues have “grown up” and moved away from home. Each now lives in a new place and has their own job and they have come home for the anual family reunion.Your job is write story that details their conversation as they all get together and discuss where they ” live” and what the now “do”. It is your decision as to the format that you would like to use. For edxample you could write story in paragraph that identifies the job and location of each

Explanation:

6 0
2 years ago
Which feature is not the result of a glacier carving out rock as it moves
Kryger [21]
<span> The feature which is not the result of a glacier carving out rock as it moves is

</span><span>A. Terminal Moraine
</span><span>
The feature  which is the result of a glacier carving out rock as it moves is 
</span>A. Roche Moutonnees

Explanation
:
 Rôche moutonnée (or sheepback) could be a rock formation created by the passing of an ice mass. The passage of ice mass ice underlying bedrock usually leads to uneven erosional forms as a result of abrasion on the "stoss" (upstream) facet<span> of the rock and plucking on the "lee".
</span>
A terminal ground<span> </span>conjointly referred to as finish ground<span>, </span>could be a form of ground<span> that forms at the snout (edge) of an </span>ice mass<span>, marking its </span>most<span> advanced. At </span>now<span>, </span>rubble<span> that has accumulated by plucking and abrasion.</span>
6 0
2 years ago
Read 2 more answers
Which of the following choices correctly matches a tool and its proper application?
Alecsey [184]

Answer:

The correct answer is option A. "cell fractionation to study the function of specific organelles".

Explanation:

Cell fractionation is a scientific process used to study the function of specific organelles, which main idea is to fractionate the cells but preserving the individual function of the elements of the cell. Usually, the separation takes place by a centrifugation method. This methodology was developed to identify the location of the organelles within the cells, but nowadays is used to study its functions.

8 0
2 years ago
Jermaine used 12 newtons of force to push a box 4 meters down the driveway. How much work, measured in joules (J), did he do to
rodikova [14]
48 because the formula for work is w=f•d so when you plug f and d in its 12 times 4, giving you 48.
6 0
2 years ago
A student views the image of a cell magnified 40000 times the image is 50mm long calculate the actual length of the sample in mi
igor_vitrenko [27]

Answer:

  1.25 µm

Explanation:

The cell will have a length dimension that is 1/40000 times the length of the image:

  (50·10^-3 m)/(40·10^3) = 1.25·10^-6 m = 1.25 µm

8 0
2 years ago
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