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arlik [135]
2 years ago
8

Sasha says that she drew an acute isosceles triangle with side lengths of 6 cm, 9 cm, and 12 cm and angles of 30°, 50°, and 100°

. Danielle says that is not possible. Explain, using sides and angles, who is correct.
Mathematics
1 answer:
quester [9]2 years ago
6 0

Danielle is correct that it is not possible to draw an acute isosceles triangle with side lengths of 6 cm, 9 cm, and 12 cm and angles of 30°, 50°, and 100°.

<em><u>Solution:</u></em>

Given that,

Sasha says that she drew an acute isosceles triangle with side lengths of 6 cm, 9 cm, and 12 cm and angles of 30°, 50°, and 100°

<em><u>Given that she drew a acute isosceles triangle</u></em>

Let us understand about isosceles triangle

An isosceles triangle is a triangle with (at least) two equal sides and also two of the angles are equal.

But given sides are of length 6 cm, 9 cm and 12 cm

Therefore, all sides are of different length. So it does not form a isosceles triangle

<em><u>Given that she drew a acute isosceles triangle</u></em>

Let us understand about acute angle

An acute triangle has three angles that each measure less than 90 degrees.

For any acute isosceles triangle two sides and two angles are equal .Each angle is less than 90 degrees.

But given angles measure 30°, 50°, and 100°

Here, one angle is greater than 90 degrees and any two angles are not equal.

Therefore, all angles measure different degrees, so they cannot form a acute isosceles triangle

Thus Danielle is correct that it is not possible to draw an acute isosceles triangle with side lengths of 6 cm, 9 cm, and 12 cm and angles of 30°, 50°, and 100°.

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Answer:

Correlation will not change.

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Step-by-step explanation:

We are given the following in the question:

Correlation coefficient between hours spent studying and hours spent on the Internet = -0.72

Properties of correlation coefficient:

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Thus, if the units of each variable is changed from hours to minutes, the correlation coefficient remains the same between minutes studying and minutes spent on the Internet.

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a computer shop charges 20 pesos per hour (or a fraction of an hour) for the first two hours and additional 10 pesos per hour fo
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The equation for the price, as a function of time in hours is:

P(x) = 20*x    for 0 ≤ x ≤ 2

P(x) = 40 + 10*(x - 2)  for  2 ≤ x

Now, we want to evaluate this function in 40 mins.

we know that 1 hour = 60mins.

Then 40 mins = (40/60) hours = 0.67 hours.

Then we input this in our function, and because this is smaller than 2, we use the first piece of our function:

P(0.67) = 20*0.67 = 13.4

So in 40 mins, the charge will be 13.4 pesos.

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A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of
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A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of healthy volunteers. For​ example, a phase I test of a specific drug involved only 7 subjects.

Step-by-step explanation:

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A welder drops a piece of red-hot steel on the floor. The initial temperature of the steel is 2,500 degrees Fahrenheit. The ambi
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Answer: After 18.05 minutes, the temperature of steel becomes 100 degrees.

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Since we have given that

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At t = 0,

we get that

f(t)=Ce^{-kt}+80\\\\2500=C+80\\\\2500-80=C\\\\2420=C

After 2 minutes, the temperature of the steel is 1500 degrees.

so, it becomes,

1500=2420e^{-2k}+80\\\\1500-80=2420e^{-2k}\\\\\dfrac{1420}{2420}=e^{-2k}\\\\0.587=e^{-2k}\\\\\ln 0.587=-2k\\\\-0.533=-2k\\\\k=\dfrac{0.533}{2}\\\\k=0.266

So, We need to find the number of minutes when the temperature of steel would be 100 degrees.

So, it becomes,

100=2420e^{-0.266t}+80\\\\100-80=2420e^{-0.266t}\\\\20=2420e^{-0.266t}\\\\\dfrac{20}{2420}=e^{-0.266t}\\\\\ln \dfrac{20}{2420}=-0.266t\\\\-4.8=-0.266t\\\\t=\dfrac{4.8}{0.266}\\\\t=18.05

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