So the ratio is 1 to 2 to 5
so basically 1 unit of soda water to 2 units of fruit punch to 5 units of ginger ale
total is 1+2+5=8 units
so 4 gallons=8 units
divide by 8
1/2 gallon=1 unit
soda water=1 unit=1/2 gallon
fruit punch=2 unit=1/2 times 2=1 gallon
ginger ale=5 unit=5 times 1/2=5/2=2 and 1/2 gallon
soda water=1/2 gallon
fruit punch concentrate=1 gallon
ginger ale=5/2 gallon or 2 and 1/2 gallon
Answer:
a) 1 tsp.
b) 1.5 tsp.
c) 2 tsp.
Step-by-step explanation:
Complete Correct Question
Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog
- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.
- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.
- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.
Solution
a) 18 kg adult dog
The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.
9 kg dog weight = (1/2) tsp
18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.
b) 6 kg cat
The dosage listed for adult cat is 1/4 tsp per 1 kg weight.
1 kg cat = (1/4) tsp
6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.
c) 18 kg pregnant dog
The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.
4.5 kg dog weight = (1/2) tsp
18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.
Hope this Helps!!!
In this case, we will use our Pythagorean Theorem.
a = 84
b = 13
c = x

Thus,
x = 85.
Answer:
a)0,45119
b)1
Step-by-step explanation:
For part A of the problem we must first find the probability that both people in the couple have the same birthday (April 30)

Now the poisson approximation is used
λ=nP=80000*1/133225=0,6
Now, let X be the number of couples that birth April 30
P(X ≥ 1) =
1 − P(X = 0) =

P(X ≥ 1) = 0,45119
B) Now want to find the
probability that both partners celebrated their birthday on th, assuming that the year is 52 weeks and therefore 52 thursday

Now the poisson approximation is used
λ=nP=80000*52/133225=31.225
Now, let X be the number of couples that birth same day
P(X ≥ 1) =
1 − P(X = 0) =

P(X ≥ 1) = 1
General exponential equation
y = A(1+r)^x
where
A = initial value
r = rate increase (+) or decrease (-)
x = time period of the change
y = projected value
y = 300(1.05)^x
in this problem, x = years after 2017
we want to find an x that makes the value more than or equal to 650
650 <= 300(1.05)^x