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2 years ago

True or False: A class that implements an interface may only implement a few of that interface's method declarations

Computers and Technology

1 answer:

Umnica [9.8K]2 years ago

8 0

Answer:

False

Explanation:

Whenever a class implements an interface, it has to define all the functions which are declared in the interface because in the interfaces, methods are only declared and not defined, so, if a method is left undefined, it leads to compilation error, that is why, all methods of an interface has to be defined by the class which is implemented that method.

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A computer application such as Microsoft Access that is used to store data and convert it into information is a ________________

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All data is stored in table

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2 years ago

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Ierofanga [76]

Answer:

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Explanation:

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2 years ago

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Evgesh-ka [11]

Answer is productivity

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2 years ago

Given a scanner reference variable named input that has been associated with an input source consisting of a sequence of strings

Makovka662 [10]

The code that examines all the strings in the input source and determines how long the longest string (or strings are) is the following:

total = 0; % initial value is zero, in every while loop it will be incremented

while(input.hasNextInt()){

total += input.nextInt( );

}

7 0

1 year ago

Read 2 more answers

You have been tasked with building a URL file validator for a web crawler. A web crawler is an application that fetches a web pa

mixas84 [53]

Answer:

Python Code:

def validate_url(url):

#Creating the list of valid protocols and file name extensions

valid_protocols = ['http', 'https', 'ftp']

valid_fileinfo = ['.html', '.csv', '.docx']

#splitting the url into two parts

url_split = url.split('://')

isProtocolValid = False

isFileValid = False

#iterating over the valid protocols and file names for validity

for x in valid_protocols:

if x in url_split[0]:

isProtocolValid = True

break

for x in valid_fileinfo:

if x in url_split[1]:

isFileValid = True

break

#Returning the result if the URL has both valid protocol and file extension

return (isProtocolValid and isFileValid)

url = input("Enter an URL: ")

print(validate_url(url))

Explanation:

The image of the output code is attached. Hope it helps.

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2 years ago