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LUCKY_DIMON [66]
2 years ago
7

Given a grid with 15 sections, determine how many sections in the grid need to be shaded so the probability of a point chosen at

random in the shaded area is exactly 0.8. Explain your reasoning
Mathematics
2 answers:
Nikitich [7]2 years ago
8 0

Answer:

12

Step-by-step explanation:

0.8 is equal to 80%

you need to figure out 80% of 15

100% = 15

10% = 1.5

(x8)

80% = 12

you would need to shade 12 out of 15 boxes which gives 0.8 chance of picking a shaded one

V125BC [204]2 years ago
4 0

Answer:

Sample answer: The number of squares that are shaded divided by 15 must equal 0.8, so the number of squares must be 0.8(15), which equals 12. The fraction 12/15 reduces to 4/5 which is equal to 8/10.

Step-by-step explanation:

The sample answer on edge

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Arnob, Bella, Colin, Dante, and Erin are going to a baseball game. They have a total budget of $100.00 to spend. Each game ticke
finlep [7]

Answer:

they can get at most 6 drinks

Step-by-step explanation:

5 (17.5) + 2x ≤100

87.5 + 2x≤100

2x≤ 12.5

x≤6.25

4 0
2 years ago
Read 2 more answers
Which is greater 9000cm or 2 km?
satela [25.4K]
Convert 2 km into cm

1 km = 100,000 cm

2 km = 200,000 cm

therefore 9,000 cm is greater
6 0
2 years ago
A student repeatedly measures the mass of an object using a mechanical balance and gets the following values: 560 g, 562 g, 556
MrRissso [65]

Answer: 2.76 g

Step-by-step explanation:

The formula to find the standard deviation:-

\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}

The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.

Then,  \overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560

Now, \sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76

Then, \sigma=\sqrt{\dfrac{76}{10}}=\sqrt{7.6}=2.76

Hence, the  standard deviation of his measurements = 2.76 g

6 0
2 years ago
9
Alexeev081 [22]

<em>so</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>3</em><em>6</em><em>.</em>

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7 0
2 years ago
Read 2 more answers
The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. Determine the foll
Mrrafil [7]

Answer

given,

thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

X = U[0.95,1.05]           0.95≤ x ≤ 1.05

the cumulative distribution function of flange

F(x) = P{X≤ x}=\dfrac{x-0.95}{1.05-0.95}

                     =\dfrac{x-0.95}{0.1}

b) P(X>1.02)= 1 - P(X≤1.02)

                   = 1- \dfrac{1.02-0.95}{0.1}

                   = 0.3

c) The thickness greater than 0.96 exceeded by 90% of the flanges.

d) mean = \dfrac{0.95+1.05}{2}

              = 1

   variance = \dfrac{(1.05-0.95)^2}{12}

                  = 0.000833

4 0
2 years ago
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