Answer:
The basic comaprism of OSSTMN and PTES includes the following: OSSTMN is more theoretical, security assessment methodology, and Metrics based why PTES is technology oriented, penetration testing methodology
, extended analysis of all stages
Explanation:
Solution
Penetration testing has several methodologies which include :OSSTMM and PTES
The comparison between OSSTMM and PTES is stated as follows:
OSSTMM:
Security assessment methodology
More Theoretical
Metrics based
PTES
:
Technology oriented
Penetration testing methodology
Extended analysis of all stages
Now,
There are 7 stages which is used to define PTES for penetration testing.(Penetration Testing Execution Standard)
- Pre-engagement Interactions
Now,
The OSSTMM is used to obtain security metrics and performing penetration testing .The OSSTMM provides transparency to those who have inadequate security policies and configurations.
The OSSTMM includes the entire risk assessment process starting from requirement analysis to report creation.
Six areas are covered by OSSTMM which are:
-
Internet technology security
Answer: True
Explanation:
Yes, the given statement is true that the RFID tags are basically used in the secure system because it is impossible to counterfeit.
RFID basically stand for the radio frequency identification that provide a method to retrieve the data or information quickly from the system. It basically used as radio wave technology in which we can easily track the objects and people by using proper programmed data.
The tag is basically placed in the object for unique identification. There are basically two types of tags in the RFID that is active and passive.
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
#include <stdio.h>
int main(void) {
// your code goes here
//unsigned a =float_times_four(0x80000000);
unsigned float_times_four(unsigned uf){
unsigned expn = (uf >> 23) & 0xFF;
printf(expn);
unsigned sign = uf & 0x80000000;
unsigned frac = uf & 0x007FFFFF;
if(expn == 255 ||(expn == 0 && frac ==0))
return uf;
if(expn){
expn<<2;
}else if(frac == 0x007FFFFF){
//here 0x7FFFFF given by you that is wrong you place this 0x007FFFFF will excute
frac>>2;
expn<<2;
}else{
frac<<=2;
}
return (sign) | (expn <<23) | (frac);
}
return 0;
}
