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barxatty [35]
2 years ago
5

CodeHS Python Rainforest Exercise 5.4.7: Categories

Computers and Technology
1 answer:
nalin [4]2 years ago
7 0

Answer:

List=[['Computers','IT','Programming'],['Maths', 'Algebra', 'Geometry']]

i=0

k=0

for i in range(0,2):

   print("Category:"+List[i][0])

   for k in range(1,3):

       print("\t"+List[i][k])

   

Explanation:

The required program is as above. We have used here a multidimensional list. The 0 of each row has the category,and rest are sub categories. The program above has limitations but is good enough to explain the fundamentals required.

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mihalych1998 [28]

Answer:

The advantage for the above condition is as follows:-

Explanation:

  • If a user creates a defined constant variable and assigns a value on its and then uses that variable instead of the value, then it will a great advantage.
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Exponentiation Is a/an operater?​
garik1379 [7]

Answer:

Yes it is

Hope this helps

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1 year ago
Which of the following can be managed using Active Directory Users and Computers snap-in?
Goryan [66]

Answer:

The answer is "Option b".

Explanation:

The active directory can manage the data with active directory customers but a snap-on machine. It is used in scrolling the list, as the earlier replies demonstrate. It will appear on the screen if there is no other startup software installed on a computer.  

This snap-on desktop is only a component, that allows its simultaneous use of different systems or devices on the very same system. It also turns the objects more or less into the pieces of the whole.

7 0
2 years ago
a.Write a Python function sum_1k(M) that returns the sum푠푠= ∑1푘푘푀푀푘푘=1b.Compute s for M = 3 by hand and write
stealth61 [152]

Answer:

def sum_1k(M):

   s = 0

   for k in range(1, M+1):

       s = s + 1.0/k

   return s

def test_sum_1k():

   expected_value = 1.0+1.0/2+1.0/3

   computed_value = sum_1k(3)

   if expected_value == computed_value:

       print("Test is successful")

   else:

       print("Test is NOT successful")

test_sum_1k()

Explanation:

It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.

- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.

- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message

- Call the <em>test_sum_1k()</em> to see the result

8 0
1 year ago
Write a method that accepts a String object as an argument and displays its contents backward. For instance, if the string argum
Nata [24]

Answer:

// importing the necessary libraries

import java.util.Scanner;

public class BackwardString {

public static void main(String[] args) {

String input;

// Scanner object to read string from user input

Scanner scanner = new Scanner(System.in);

System.out.print("Enter String here : ");

input=scanner.next();

// calling backward method to reverse passed string

backward(input);

// closing Scanner object

scanner.close();

}

// Method to Reverse the input string

private static void backward(String source) {

int i, len = source.length();

StringBuilder dest = new StringBuilder(len);

for (i = (len - 1); i >= 0; i--){

dest.append(source.charAt(i));

}

System.out.println("Reversed String : "+dest);

}

}

Explanation:

// importing the necessary libraries

import java.util.Scanner;

public class BackwardString {

public static void main(String[] args) {

String input;

// Scanner object to read string from user input

Scanner scanner = new Scanner(System.in);

System.out.print("Enter String here : ");

input=scanner.next();

// calling backward method to reverse passed string

backward(input);

// closing Scanner object

scanner.close();

}

// Method to Reverse the input string

private static void backward(String source) {

int i, len = source.length();

StringBuilder dest = new StringBuilder(len);

for (i = (len - 1); i >= 0; i--){

dest.append(source.charAt(i));

}

System.out.println("Reversed String : "+dest);

}

}

The program above accepts a String object as an argument and displays its contents backward.

It reverses the any string inputed while producing the output.

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