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netineya [11]
2 years ago
8

The rabbit population in a certain area is 500​% of last​ year's population. There are 1,100 rabbits this year. How many were th

ere last​ year?
Mathematics
1 answer:
andreev551 [17]2 years ago
8 0

Answer:

5,500 rabbits

Step-by-step explanation:

500% of something is 5 times the original amount. 1,100 rabbits times 5 equals 5,500.

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Two different samples will be taken from the same population of test scores where the population mean and standard deviation are
Alenkinab [10]

Answer:

The sample consisting of 64 data values would give a greater precision.

Step-by-step explanation:

The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{n}}

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).

That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.

Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.

The two sample sizes are:

<em>n</em>₁ = 25

<em>n</em>₂ = 64

The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.

Width for n = 25:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]        

Width for n = 64:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]

Thus, the sample consisting of 64 data values would give a greater precision

5 0
2 years ago
Read 2 more answers
Ava wants to figure out the average speed she is driving. She starts checking her car’s clock at mile marker 0. It takes her 4 m
VLD [36.1K]
<h2>Answer:</h2>

The average speed of car is:

                 0.75 miles per minutes.

The equation of line is:

                    n=\dfrac{3}{4}t

<h2>Step-by-step solution:</h2>

The table that describes the time and number of  miles marked is given by:

Time       Miles

  0              0

  4               3

  8               6

Clearly we could observe that with the increase in time by every 4   minutes the number of mile increases by 3.

i.e. the average speed is calculated as the ratio of change in miles to the change in time.

Hence,

Average\ Speed=\dfrac{3-0}{4-0}\\\\\\i.e.\\\\\\Average\ Speed=\dfrac{3}{4}=0.75

Hence, the average speed=0.75 miles per minutes.

Also we will find the equation of the lines that related the miles and time by using the two-point formula.

i.e. any line passing through (a,b) and (c,d) is calculated by using the formula:

y-b=\dfrac{d-b}{c-a}\times (x-a)

Here (a,b)=(0,0) and (c,d)=(4,3)

i.e. the equation is given by:

n-0=\dfrac{3-0}{4-0}\times (t-0)\\\\i.e.\\\\n=\dfrac{3}{4}t

6 0
2 years ago
Read 2 more answers
Rahzel wants to determine how much gasoline he and his wife use in a month.He calculated that he used 78 1/3 gallons of gas last
attashe74 [19]
52. Rahzel wants to determine how much gasoline they had every month => He used 78 1/3 gallons of gas monthly => his wife used 41 3/8 gallons of gas last month How much is to total of gas that they both used. First let’s convert this fraction to decimal => 78 1/3 = 78.33 => 41 3/8 = 41.38 Now, let’s start adding. => 78.33 + 41.38 = 119.71 this is already rounded to the nearest hundredths.
7 0
2 years ago
Simplify 100y^3/98xy pls answer soon hegarty maths lazy
OleMash [197]

Answer:

50y^4x/49

Step-by-step explanation:

y^3/98

((100* y^3/98 * x) * y

2.1 y^3 * y^1=y^(3+1)=y^4

8 0
2 years ago
Jaleel and Lisa are simplifying the expression 2 (x minus 2) + 2 as shown. Jaleel’s Method 2 (x minus 2) + 2 = 2 x minus 4 + 2 =
Art [367]

Answer:

(D)Jaleel's method is correct because 2(x-2)=2x-4.

Step-by-step explanation:

Jaleel and Lisa are simplifying the expression 2(x-2)+2 as shown.

J$aleel's Method: \left\{\begin{array}{ccc}2 (x -2) + 2 \\= 2 x - 4 + 2 \\= 2 x - 2\end{array}\right

L$isa's Method: \left\{\begin{array}{ccc}2 (x-2) + 2 \\= 2 x -2 + 2 \\= 2 x\end{array}\right

We can see that Jaleel's method is correct because:

2(x-2)=2x-4.

When you expand, you must multiply the term outside by all the terms inside the bracket.

The correct option is D.

6 0
2 years ago
Read 2 more answers
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