Answer:
The code to this question can be given as:
Code:
int i,j,count_previous=0,count_next=0; //define variable
for (j=0; j<n; j++) //loop for array
{
if (x[0]==x[j]) //check condition
{
count_previous++; //increment value by 1.
}
}
for (i=0; i<n; i++) //loop
{
for (j=0; j<n; j++)
{
if (x[i]==x[j]) //check condition
{
count_next++; //increment value by 1.
}
}
if (count_previous>count_next) //check condition
{
mode=x[i-1];
}
else
{
mode=x[i];
count_previous=count_next; //change value.
count_next= 0 ; //assign value.
}
}
Explanation:
In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.
Answer:
cubeVolume = IMath.toThePowerOf(cubeSide, 3);
Explanation:
Following is the explanation for above statement:
Left side:
cubeVolume is a variable with data-type int, it will store the integer value that is the output from right side.
Right side:
- IMath is the class name.
- toThePowerOf is the built-in function that takes two arguments of data type int. First is the base and second is the power(exponent) separated by comma. In place of first argument that is the base variable we will pass the variable cubeSide that has been declared and initialize.
- Now the output will be stored in the variable cubeVolume.
i hope it will help you!
Since Greg wants to become an advertising and promotions manager, he needs to at least gain a (B) bachelor’s degree level of education, since generally, this educational background is expected from individuals who wishes to work in an entry-level position in the field of advertising.
One of the skills that he also needs to develop is (C) communication skills, because he would have to be able to communicate in both written and spoken to develop the advertisements according to the client’s desires.
Answer:
C
Explanation:
Putting all government forms on the city web site is the least activity likely to be effective in the purpose of reducing digital divide.
Holding basic computer classes at the community centers will very much help to reduce the digital divide.
Providing free wireless internet connections at locations in low-income neighborhood will also reduce the gap of digital divide
Requiring that every city school has computers that meet a minimum hardware and software will made computing resources available to users thereby reducing digital divide.
Answer:
I. hatching
II. filter
Explanation:
Sarah is creating an image. She wants to achieve tonal effects with parallel lines by varying their densities and distribution patterns. She will use <u>hatching</u> to do this. She also wants to add special effects on the image. Therefore, she will use <u>filters</u>.
Hatching refers to an art technique in which parallel lines are used to shade by drawing them closely together.
Stippling is an art technique used in the making of patterns by using small dots.
Filters is a technique of changing image characteristics. It is used to change the picture characteristics & to add special effects to an image such as the shade, contrast, tone, brightness etc.
We therefore see that, <u>hatching</u> and <u>filter</u> are the correct answers respectively
