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masha68 [24]
2 years ago
9

If the input is negative, make numItemsPointer be null. Otherwise, make numItemsPointer point to numItems and multiply the value

to which numItemsPointer points by 10. Ex: If the user enters 99, the output should be:
Computers and Technology
1 answer:
Brilliant_brown [7]2 years ago
6 0

Answer:

The code for the given statements are described below.

Explanation:

// Place code below in line 9

if(numItems < 0)  // starting of a loop

{

numItemsPointer = NULL;

}

else  

{

numItemsPointer = &numItems;

numItems = numItems * 10;   // items multiplied by 10

}   // ending of a loop

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Given three dictionaries, associated with the variables, canadian_capitals, mexican_capitals, and us_capitals, that map province
Nookie1986 [14]

Answer:

The Python code to combine the three dictionaries are is given as follows:

  1. canadian_capital = {
  2.    cash: "SOME VALUES",
  3.    assets: "SOME VALUES"
  4. }
  5. mexican_capital = {
  6.    cash: "SOME VALUES",
  7.    assets: "SOME VALUES"
  8. }
  9. us_capital = {
  10.    cash: "SOME VALUES",
  11.    assets: "SOME VALUES"
  12. }
  13. nafta_capital = {
  14.    canadian: canadian_capital,
  15.    mexican : mexican_capital,
  16.    us: us_capital
  17. }

Explanation:

<u>Line 1 - 14 :</u>

Create three Python dictionaries and name them as <em>canadian_capitals, mexican_capital </em>and<em> us_capitals</em>. Please note a Python dictionaries should be enclosed in curly braces { }.  

We just define two samples of relevant keys (<em>cash </em>and <em>asset</em>) in each of the dictionaries. Python dictionary can map a key to a value.

Since we are not given any capital values from the question,  a dummy string "<em>SOME VALUES</em>" is tentatively set as the value for each of the keys.

In practice, we should replace those dummy strings with the real values of capital. The values can be a number, a string, a list and even a nested dictionary.

<u>Line 16 - 20 : </u>

Create one more Python dictionary and name it as <em>nafta_capital</em>.

Since our aim is to combine the three previous dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em>) and associate it with <em>nafta_capital</em>, we can define three different keys (<em>canadian, mexican </em>and <em>us</em>) in our dictionary nafta_capital.

As mentioned, a value associated with a key can be a nested dictionary. Hence, we just map <em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> as the value of the keys (<em>canadian, mexican </em>and<em> us</em>) in dictionary<em> nafta_capital,</em> respectively,

By doing so, we have managed to combine three target dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> ) into a single dictionary, <em>nafta_capital</em>.

4 0
2 years ago
You are a high school student learning about computers and how to build them. As a class project, you have built a new computer.
Anon25 [30]

Answer:

You can use thermal paste, active heat sink, liquid pipes, and even a fan. These are just some that I've heard.

Explanation:

All of these are cooling and will stop the Central Processing Unit from overheating.

Hope this helps :)

5 0
1 year ago
Write the definition of a function named quadratic that receives three double parameters a, b, c. If the value of a is 0 then th
VMariaS [17]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

//initialize function quadratic

void quadratic(double, double, double);

int main() {

   //declare double variables a, b and c

   double a,b,c;

   //take input from user

   cin>>a>>b>>c;

   //call function quadratic

   quadratic(a,b,c);

return 0;

}

void quadratic(double a, double b, double  c){

   double root,n;

   //check if variable a is equal to zero

   if(a==0){

       cout<<"no solution for a=0"<<endl;

       return;

   }

   //check if b squared - 4ac is less than zero

   else

   if(((b*b)-(4*a*c))<0){

       cout<<"no real solutions"<<endl;

       return;

   }

   //print the largest root if the above conditions are not satisfied

   else{

       n=((b*b)-(4*a*c));

       root=(-b + sqrt(n)) / (2*a);

       cout<<"Largest root is:"<<root<<endl;

   }

   return ;

}

Explanation:

Read three double variables a, b and c from the user and pass it to the function quadratic. Check if the value of variable a is equal to zero. If true, print "no solution for a=0". If this condition is false, check if b squared - 4ac is less than zero. If true, print "no real solutions". If this condition is also false, calculate the largest solution using the following formula:

largest root = (-b + square root of (b squared - 4ac)) / (2*a)

Input 1:

2 5 3

Output 2:

Largest root is:-1

Input 2:

5 6 1

Output 2:

Largest root is:-0.2

5 0
2 years ago
Which security control is most helpful in protecting against eavesdropping on wireless LAN (WLAN) data transmissions that would
3241004551 [841]

Answer:

D. Applying strong encryption

Explanation:

Strong cryptography or cryptographic-ally strong are general terms applied to cryptographic systems or components that are considered highly resistant to cryptanalysis.One cryptographic cipher has been mathematically proven to be unbreakable when it is used correctly, but it is only very rarely used.

6 0
2 years ago
​to add notes or comments, insert a comment tag using the syntax _____.
Aneli [31]
The needed syntax would be:
<!--comment-->
Hope I could be of assistance! ;)
4 0
2 years ago
Read 2 more answers
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