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Fynjy0 [20]
2 years ago
11

What is 12x3-9x2 - 4x + 3 in factored form?

Mathematics
2 answers:
Ludmilka [50]2 years ago
7 0

Answer:

(4x-3)(3x²-1)

Step-by-step explanation:

12x³-9x²-4x+3

3x²(4x-3)-1(4x-3)

Taking 4x-3 common

(4x-3)(3x²-1)

masya89 [10]2 years ago
6 0

Answer:

(4X-3)(3X^2-1)

Step-by-step explanation:

12X^3-9X^2-4X+3=

3X^2*(4X-3)-(4X-3)=

(4X-3)(3X^2-1)

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In 1900, there was an Olympic underwater swimming event. The score was calculated by giving one point for each second the swimme
mash [69]
68.4*1= 68.4   60.2*2= 120.4   68.4+120.4=    188.8
4 0
2 years ago
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Solve the trigonometric equation in the interval [0, 2π). Give the exact value, if possible; otherwise, round your answer to two
svp [43]

Answer:

θ∈{\frac{\pi }{8},\frac{5\pi }{8},\frac{9\pi }{8},\frac{13\pi }{8}}

Explanation:

The given equation is

sin(2\theta )-cos(2\theta )=0

\Rightarrow sin(2\theta )=cos(2\theta )\\\\\therefore \frac{sin(2\theta )}{cos(2\theta )}=1\\\\tan(2\theta )=1\\\\\therefore 2\theta =n\pi +\frac{\pi}{4}\\\\\therefore \theta =\frac{n\pi }{2}+\frac{\pi }{8}

Applying values on 'n' we obtain values of θ that beling to [0,2π)

For n=0, θ=\frac{\pi }{8}

For n=1, θ =\frac{5\pi }{8}

For n=2,θ =\frac{9\pi }{8}

For n=3,θ =\frac{13\pi }{8}

6 0
2 years ago
Karen walked three miles in 48 mins. Bob walked one mile further than Karen. If it took Bob 1 hour and 5 min to complete his wal
nlexa [21]

Answer:

Karen

Step-by-step explanation:

Karen because it took bob and extra minute to walk the last mile.

8 0
2 years ago
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An attempt to establish a video call via some social media app may fail with probability 0.1. If connection is established and i
xxMikexx [17]

Answer:

(1). y = x ~ Exp (1/3).

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

Step-by-step explanation:

Kindly check the attachment to aid in understanding the solution to the question.

So, from the question, we given the following parameters or information or data;

(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.

(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "

(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."

(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.

8 0
2 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
2 years ago
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