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Annette [7]
2 years ago
6

Which graph represents a proportional relationship? On a coordinate plane, a straight line crosses the y-axis at (0, 0). On a co

ordinate plane, a straight line crosses the y-axis at (0, negative 2). On a coordinate plane, a straight line crosses the y-axis at (0, negative 3). On a coordinate plane, a straight line crosses the y-axis at (0, 3).
Mathematics
2 answers:
Ugo [173]2 years ago
8 0

Answer:

a

Step-by-step explanation:

DIA [1.3K]2 years ago
4 0

Answer:

On a coordinate plane, a straight line crosses the y-axis at (0, 0)

Step-by-step explanation:

proportional formula:   y = kx     k is constant

A graph of a proportional relationship is a straight line that passes through the origin

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joyce is helping her aunt create craft kits. her aunt has 138 pipe cleaners, and each kit will include 6 pipe cleaners. what is
Andre45 [30]
23 pipe cleaners cause 23 x 6= 138
5 0
2 years ago
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If sin theta = sqrt(2/2), which could not be the value of theta?
Nataliya [291]

The solution would be like this for this specific problem:

sin(θ°) = √(2)/2 

θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° − sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ 

360°*0 + 45° = 45° 
360°*0 + 135° = 135° 
360°*1 + 45° = 405° 

<span>sin(225°) = -√(2)/2

</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta cannot be 225 degrees.

4 0
2 years ago
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A closed cylindrical tank contains 36pi cubic feet of water and is filled to half its capacity. When the tank is placed upright
pentagon [3]

Answer:

2.12 ft above ground level

Step-by-step explanation:

Volume of the cylindrical tank is 36*π

Tank is filled to half its capacity, that means tank is filled 18*π, and level of water is 4 feet, then the height of the cylinder is 8 feet

With the above information we can calculate the radius of the base of the cylinder, according to

V  =  36*π  = π*r²*h     ⇒  36 = r²*h     ⇒   36/8 = r²    ⇒  r = 2.12 ft

Then the radius of the base is  2.12 ft

When the cylindrical tank is place on its side, the level of water inside have to be 2.12 ft above ground level. That is the level of half its capacity

7 0
2 years ago
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Daniel wants to predict how far he can hike based on the time he spends on the hike. He collected some data on
horsena [70]

Answer:

Daniel can read his data and refer to line as best line of fit and estimate an average per set of hours.

Step-by-step explanation:

A line of fit draws a solid conclusion to the average for the hours spent during the amount of indicated hours. We draw a line of fit central fit and aim similar centrality as that similar results of the mean (without working out the mean we can draw a line perpendicular to the number of mean, but in line of fit we go central to all the descending or cascading results to include all results but just using one line), with one further consideration and that is balance if anything sticks out from the norm ie) weather conditions including data, we suggest if there is nothing to weigh the line of fit to a balancing outcome that shows the opposite of kilometres walked (eg. extreme higher mileage within the hour/s) then it may just alter the line a fraction of how many treks he did, but not in data less than 30 entries. Have attached an example where they classify in economics something outside the norm is called a misfit. Daniel can read his data and refer to line as best line of fit and estimate an average per set of hours. Here on the attachment you can read any misfit info and use the line coordination perpendicular to guide the indifference, the attachment shows it is not really included in the best line of fit as other dominating balances have occurred and therefore we have a misfit, all whilst using best line of fit to balance everything fairly.

7 0
2 years ago
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What is the perimeter of rhombus WXYZ?
oksian1 [2.3K]

<u>Answer</u>:

The perimeter of rhombus WXYZ is 4 \sqrt{13}

<u>Step-by-step explanation:</u>

Step 1 :Finding length  of  XY

Distance formula  = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

here

x_1= 5

x_2=3

y_1= -1

y_2=2

XY  = \sqrt{(3-5)^2 +(2 -(-1))^2}

XY  = \sqrt{(3-5)^2 +(2 +1))^2}

XY  = \sqrt{(-2)^2 +(3))^2}

XY  = \sqrt{4 +9}

XY  = \sqrt{(13)}

Step 2 :Finding length  of  YZ

Distance formula  = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

here

x_1= 3

x_2=5

y_1= 2

y_2=5

YZ  = \sqrt{(5-3)^2 +(5-2)^2}

YZ = \sqrt{(2)^2 +(3)^2}

YZ = \sqrt{4 +9}

YZ  = \sqrt{(13)}

Step 3 : :Finding length  of  ZW

Distance formula  = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

here

x_1= 5

x_2=7

y_1= 5

y_2=2

ZW = \sqrt{(7-5)^2 +(5-2)^2}

ZW  = \sqrt{(2)^2 +(3)^2}

ZW  = \sqrt{4 +9}

ZW = \sqrt{(13)}

Step 4 :Finding length  of  WX

Distance formula  = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}

here

x_1= 7

x_2=5

y_1= 2

y_2= -1

WX = \sqrt{(7-5)^2 +((-1)-2)^2}

WX  = \sqrt{(2)^2 +(-3)^2}

WX  = \sqrt{4 +9}

WX = \sqrt{(13)}

Step 5: finding the perimeter of the rhombus

Perimeter= 4 X side

=> 4 \times \sqrt{13}

=> 4 \sqrt{13}

5 0
2 years ago
Read 2 more answers
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