Answer:
1,496 new car buyers
Step-by-step explanation:
The sample size n in Simple Random Sampling is given by

where
z = 1.645 is the critical value for a 90% confidence level (*)
p= 0.33 is the population proportion.
e = 0.02 is the margin of error
so

<em>(*)</em><em>This is a point z such that the area under the Normal curve N(0,1) inside the interval [-z, z] equals 90% = 0.9</em>
It can be obtained in Excel or OpenOffice Calc with
<em>NORMSINV(0.95)</em>
3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
Answer: The proportion of students spending at least 2 hours on social media equals 0.7257 .
Step-by-step explanation:
Given : The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social media.
The distribution of time on social media is known to be Normal.
Let x be the number of minutes spent on social media.
Then, the probability that students spending at least 2 hours (2 hours = 120 minutes as 1 hour = 60 minutes) on social media would be:

Hence, the proportion of students spending at least 2 hours on social media equals 0.7257 .
The solution is <span>B. π/12+nπ
</span>proof
sinx cosx = 1/4 is equivalent to 2 <span>sinx cosx = 1/2 or sin2x =1/2
so 2x = arcsin(1/2) = </span>π/6 + 2nπ, so x = π/12+nπ
Answer:
Hey there!
1.35 km/s would equal 3020 miles per hour.
Let me know if this helps :)