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yawa3891 [41]
2 years ago
15

A company has 125 personal computers. The probability that any one of them will require repair on a given day is 0.15.

Mathematics
1 answer:
mariarad [96]2 years ago
8 0

Answer:

a. the probability that any one of the computers will require repair on a given day is constant

Step-by-step explanation:

The following properties must be true in order for a distribution to be binomial:

- A fixed number of trials (125 computers)

- Each trial is independent of the others (one computer requiring repair does not interfere with the likelihood of another requiring repair).

There are only two outcomes (requires repair or do not require repair)

The probability of each outcome remains constant from trial to trial (All computers have the same likelihood of requiring repair, 0.15).

Therefore, the alternative that better fits those properties is alternative a. the probability that any one of the computers will require repair on a given day is constant

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postnew [5]
The mean is 36 and the standard deviation is 5.02.

The mean is given by
μ = np = 120*0.3 = 36.

The standard deviation is given by
σ = √(n*p*(1-p)) = √(120*0.3*0.7) = √25.2 = 5.02.
8 0
2 years ago
The owner of a football team claims that the average attendance at games is over 74,900, and he is therefore justified in moving
Slav-nsk [51]

Answer:

Option c (Upper tailed) is the correct choice.

Step-by-step explanation:

Given that:

The average attendance is:

= 74,900

We will have to test:

⇒ H_0:\mu \leq \mu_0

or,

   H_0: \mu \leq 74,900

Verses,

⇒ H_1: \mu> \mu_0

or,

    H_1: \mu >74,900

The other given alternatives aren't connected to the given scenario. So the above is the correct one.

4 0
2 years ago
Danica is in the observation area of the sears tower in chicago overlooking lake michigan. She sights two sailboats going due ea
inessss [21]

Answer:

The boats are far apart by 4506.1 feet

Step-by-step explanation:

from the graph attached

i) BC = 1353 \times tan(71\textdegree) = 2761.82 feet

ii) BD  = 1353 \times tan(58\textdegree) =  1744.28 feet

iii) the boats are far apart by = CD = CB + BD = 2761.82 + 1744.28 = 4506.1 feet

3 0
2 years ago
Direct Mailing Company sells computers and computer parts by mail. The company claims that more than 90% of all orders are maile
lys-0071 [83]

Answer:

We conclude that less than or equal to 90% of all orders are mailed within 72 hours after they are received which means the company's claim is not true.

Step-by-step explanation:

We are given that the company claims that more than 90% of all orders are mailed within 72 hours after they are received. The quality control department at the company often takes samples to check if this claim is valid.

A recently taken sample of 175 orders showed that 161 of them were mailed within 72 hours.

<u><em>Let p = percentage of all orders that are mailed within 72 hours.</em></u>

SO, Null Hypothesis, H_0 : p \leq 90%   {means that less than or equal to 90% of all orders are mailed within 72 hours after they are received}

Alternate Hypothesis, H_A : p > 90%   {means that more than 90% of all orders are mailed within 72 hours after they are received}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = proportion of orders that were mailed within 72 hours in a sample of 175 =  \frac{161}{175}\times 100  = 92%

           n = sample of orders = 175

So, <u><em>test statistics</em></u>  =  \frac{0.92-0.90}{{\sqrt{\frac{0.92(1-0.92)}{175} } } } }

                               =  0.975

The value of the test statistics is 0.975.

<em>Now at 1% significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is less than the critical value of z as 0.975 < 2.3263, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that less than or equal to 90% of all orders are mailed within 72 hours after they are received which means the company's claim is not true.

6 0
2 years ago
Jen determined the masses of 7 rocks. She recorded he mass of 6f each rock on the line plot below. On the chart there is 1/4= 2
qwelly [4]
To find the total mass you will add the following masses together:

1/4 + 1/4 + 2/4 + 2/4 + 2/4 + 3/4 + 3/4

For every X you list the number that many times.

The sum is 14/4 or 3 2/4 or
3 1/2.

The answer is choice D.
4 0
2 years ago
Read 2 more answers
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