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Viktor [21]
2 years ago
6

A town has a population of 2000 and grows at 2% every year. To the nearest year, how long will it be until the population will r

each 3000?
Mathematics
2 answers:
MissTica2 years ago
5 0

Answer:

21 years

Step-by-step explanation:

Use the equation 2000(1.02)^{x} = 3000 where x is the number of years passed.

Once you've solved for it, x=20.475319. Although it's closer to 20 years to the nearest year, it's 21 years since you'll wont reach 3000 in year 20.

Verizon [17]2 years ago
4 0

Answer:20

Step-by-step explanation:

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A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by: h(x)=-2x^2+20x+48h(x)=
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the maximum height is the y-value of the vertex.

h(x) = -2x² + 20x + 48

      <em>  a=-2, b=20, c=48</em>

x = \frac{-b}{2a} = \frac{-20}{2(-2)} = \frac{-20}{-4} = 5

h(5) = -2(5)² + 20(5) + 48

      =  -50   +  100   + 48

      =          50         + 48

      =                98

Answer: 98 meters

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2 years ago
A square and a rhombus are shown below. Which attribute is true of one of the shapes but not of both
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The rhombus has 2 obtuse angles, and 2 acute angles. the square has 4 right angles.
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5 0
2 years ago
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Lines a and b are parallel. What is the measure of ∠5 if ∠4 measures 104°?
Alborosie

Answer:

hope that this picture answers it

4 0
2 years ago
PLEASE HELP ME!
algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

2.\sum_{k=1}^{4}(2k)^{2}

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

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3.\sum_{k=3}^{6}(2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4.  The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

\sum_{j=1}^{7}(\frac{1}{4})^{j-1}

5. -5 + -1 + 3 + 7 + 11

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a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

\sum_{j=1}^{5}(4j-9)

5 0
2 years ago
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