Answer:
decreasing the pressure
Step-by-step explanation:
i just took the test
Answer: C. 70 percent
Step-by-step explanation:
Given, Time for the first unit = 50 minutes
Time for the second unit = 35 minutes
The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.
So, The unit improvement factor learning curve = 35÷ 50 × 100 = 70 percent.
Hence, the correct option is "C. 70 percent".
Answer:
<em>24 square yards</em>
Step-by-step explanation:
Find the diagram attached.
The area of the diagram = Area of rectangle + Area of triangle
Area of rectangle = 3 * 4
Area of rectangle = 12 square yards
Area of triangle = 1/2 * base * height
Area of triangle = 1/2 * 6 * 4
Area of triangle = 12 square yards
Area of the diagram = 12 + 12
Area of diagram = 24 square yards
<em>Hence 24 square yards of carpeting is needed</em>
A
function 
from a
set A to a
set B is defined as a relation that assings to each element

in the set A exactly one element

in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing
bell peppers. If each side of the
tomato patch is

feet, then we have a square patch as shown in the Figure below.
1.a) Write the function Wa(x) representing the width of the bell pepper patch.
We know that she wants its width to be half the width of the tomato patch. Let

be the width of the tomato patch, then the function that matches this statement is:
1.b) Write the function La(x) representing the length of the bell pepper patch.In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:
</span>

<span>
2. Ar</span>
ea of the bell pepper patch in terms of x.
Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:
</span>

<span>
3. C</span><span>
ombined area of the tomato patch and the bell pepper patch.
This function is the sum of both the area of the tomato patch and the bell pepper patch. So:
</span>

<span>
4. W</span>
rite the function Aa(x) for the remaining planting area in the garden.
The remaining planting area in the garden are the rectangles in red. So we need to subtract
the width of the bell pepper patch from the width of the tomato patch
and multiply it by 2. In mathematical language this is
given by:<span>
</span>

5. Find the area of the remaining space in the garden after planting tomatoes and bell peppers.
Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:
</span>

<span>
Therefore the area of the remaining space is:
</span>
Answer:
a.0.8664
b. 0.23753
c. 0.15866
Step-by-step explanation:
The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between
a. N164.50 and N185.50?
b. greater than N180.00?
c. less than N168.00?
We solve the above question using z score formula
z = (x-μ)/σ/√n where
x is the raw score,
μ is the population mean = N175
σ is the population standard deviation = N42
n is random number of sample = 36
a. Between N164.50 and N185.50?
For x = N 164.50
z = 164.50 - 175/42 /√36
z = -1.5
Probability value from Z-Table:
P(x = 164.50) = 0.066807
For x = N185.50
z = 185.50 - 175/42 /√36
z =1.5
Probability value from Z-Table:
P(x=185.50) = 0.93319
Hence:
P(x = 185.50) - P(x =164.50)
= 0.93319 - 0.066807
= 0.866383
Approximately = 0.8664
b. greater than N180.00?
x > N 180
Hence:
z = 180 - 175/42 /√36
z = 5/42/6
z = 5/7
= 0.71429
Probability value from Z-Table:
P(x<180) = 0.76247
P(x>180) = 1 - P(x<180) = 0.23753
c. less than N168.00?
x < N168.
z = 168 - 175/42 /√36
z = -7/42/6
z = -7/7
z = -1
Probability value from Z-Table:
P(x<168) = 0.15866