Answer:
The solution is written using Python as it has a simple syntax.
- def getHighScores(gameScores, minScore):
- meetsThreshold = []
- for score in gameScores:
- if(score > minScore):
- meetsThreshold.append(score)
- return meetsThreshold
- gameScores = [2, 5, 7, 6, 1, 9, 1]
- minScore = 5
- highScores = getHighScores(gameScores, minScore)
- print(highScores)
Explanation:
Line 1-8
- Create a function and name it as <em>getHighScores</em> which accepts two values, <em>gameScores</em> and <em>minScore</em>. (Line 1)
- Create an empty list/array and assign it to variable <em>meetsThreshold</em>. (Line 2)
- Create a for loop to iterate through each of the score in the <em>gameScores</em> (Line 4)
- Set a condition if the current score is bigger than the <em>minScore</em>, add the score into the <em>meetsThreshold</em> list (Line 5-6)
- Return <em>meetsThreshold</em> list as the output
Line 11-12
- create a random list of <em>gameScores</em> (Line 11)
- Set the minimum score to 5 (Line 12)
Line 13-14
- Call the function <em>getHighScores()</em> and pass the<em> gameScores</em> and <em>minScore </em>as the arguments. The codes within the function <em>getHighScores()</em> will run and return the <em>meetsThreshold </em>list and assign it to <em>highScores.</em> (Line 13)
- Display <em>highScores</em> using built-in function print().
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Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
Answer:
Pseudo CODE
a)
n= Input “Enter 5 integer value”
b)
sum=0.0
For loop with i ranging from 0 - 5
Inside loop sum=n[i]+sum
Outside loop avg= sum/5
Print avg
c)
small=n[0] # assume the first number in the list is smallest
large= n[0] # assume the first number in the list is largest
For loop with i ranging from 0 - 5
Inside loop if n[i]<small #if any another number is smaller than small(variable)
Inside if Then small=n[i]
Inside loop if n[i]>large # if any another number is larger than large(variable)
Inside if then large=n[i]
Print small
Print large
d)
print avg
print small
print large
