Answer:
The standard deviation is 4.83 inches.
Explanation:
We are given that the average yearly snowfall in Chillyville is Normally distributed with a mean of 55 inches.
The snowfall in Chillyville exceeds 60 inches in 15% of the years, we have to find the standard deviation.
Let X = <u><em>the average yearly snowfall in Chillyville</em></u>.
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= mean amount of rainfall = 55 inches
= standard deviation
Now, it is stated that the snowfall in Chillyville exceeds 60 inches in 15% of the years, that means;
P(X > 60 inches) = 0.15
P(
>
) = 0.15
P(Z >
) = 0.15
In the z table, the critical value of z that represents the top 15% of the area is given as 1.0364, that means;
= 4.83 inches
Hence, the standard deviation is 4.83 inches.
Answer: 9000
Given:
10 automatic sprinkler activated 10 minutes for 2 sessions daily.
Each sprinkler provides 1.5 gallons of water per minute
Question:
How many gallons of water is the neighbor using during a 30-day billing cycle?
Solution:
Each sprinkler provides water (10*2) or 20 minutes daily. In 20 minutes each sprinkler can provide (20*1.5) or 30 gallons of water. There are 10 sprinklers so (10*30) 300 gallons all in all daily. In 30 days, (30*300)9000 gallons of water are consumed.
54289 = 233^2
You know the last digit of the squared number is 3 or 7, so just try numbers ending with those from 220 to 250
Answer:
into ay maihahalintulad so icing pansarilling journal o talaarawang ibinabahagi as boing Mundo
Explanation: