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trapecia [35]
2 years ago
7

3.14 LAB: Simple statistics for Python

Computers and Technology
1 answer:
Ad libitum [116K]2 years ago
8 0

Answer:

Following are the correct python code to this question:

n1 = float(input('Input first number: '))#input first number  

n2 = float(input('Input second number: '))#input second number  

n3 = float(input('Input third number: '))#input third number  

n4 = float(input('Input fourth number: '))#input fourth number  

average = (n1+n2+n3+n4)/4 #calculate input number average

product = n1*n2*n3*n4 # calculate input number product

print('product: {:.0f}  average: {:.0f}'.format(round(product),round(average))) #print product and average using round function

print('product: {:.3f}  average: {:.3f}'.format(product,average)) #print product and average value

Output:

Please find the attachment.

Explanation:

The description of the above python code can be defined as follows:

  • In the above python program four variable "n1, n2, n3, and n4" is defined, in which we take input from the user end, and in these user inputs we use the float method, that converts all the input value in to float value.
  • In the next step, two variable average and product are defined, that calculate all input numbers product, average, and hold value in its variable.
  • In the last line, the print method is used, which prints its variable value by using a round and format method.

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Mrs. Johnson is here today to receive an intercostal nerve block to mitigate the debilitating pain of her malignancy. Her cancer
Furkat [3]

Answer:

The correct answer is:

a. M54.6, C79.51, C80.1

Explanation:

-  M54.6 Pain in thoracic spine. It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.

- C79.51: Secondary malignant neoplasm of bone, it is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.

- G89. 3 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM G89.

Malignant neoplasm of anus, unspecified

Neoplasm related pain (acute) (chronic)

Pain in thoracic spine. M54. 6 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.

Malignant (primary) neoplasm, unspecified

- C80. 1 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM C80.

5 0
2 years ago
Write a sequence of statements that create a file named "greeting" and write a single line consisting of "Hello, World!" to that
tia_tia [17]

Answer:

The solution code is written in Python 3 as below:

  1. outfile = open("greeting.txt", "w")
  2. outfile.write("Hello World")
  3. outfile.close()

Explanation:

To create a simple text file in Python, we can use Python built-in function, <em>open()</em>. There are two parameters needed for the open() function,

  1. the file name and
  2. a single keyword "w". "w" denote "write". This keyword will tell our program to create a file if the file doesn't exist.

The statement <em>open("greeting.txt", "w")</em> will create a text file named "<em>greeting.txt</em>" (Line 1)

To fill up the content in the greeting.txt, we use <em>write()</em> method. Just include the content string as the argument of the <em>write()</em> method. (Line 2)

At last, we use <em>close() </em>method to close the opened file,<em> outfile</em>. This will release the system resource from the<em> outfile.</em>

4 0
2 years ago
6. Write pseudo code that will perform the following. a) Read in 5 separate numbers. b) Calculate the average of the five number
Alex

Answer:

Pseudo CODE

a)

n= Input “Enter 5 integer value”

b)

sum=0.0

For loop with i ranging from 0 - 5

Inside loop sum=n[i]+sum

Outside loop avg= sum/5

Print avg

c)

small=n[0] # assume the first number in the list is smallest

large= n[0] # assume the first number in the list is largest

For loop with i ranging from 0 - 5

Inside loop if n[i]<small #if any another number is smaller than small(variable)

Inside if Then small=n[i]

Inside loop if n[i]>large # if any another number is larger than large(variable)

Inside if then large=n[i]

Print small

Print large

d)

print avg

print small

print large

8 0
2 years ago
Lynn runs the locate command and the results include many files from a directory that she doesn't want to include in her search.
Zinaida [17]

Answer:

C) /etc/updatedb.conf

Explanation:

The locate command actually uses the configuration file located at /etc/updated.conf.

5 0
2 years ago
Read 2 more answers
Given the dictionary, d, find the largest key in the dictionary and associate the corresponding value with the variable val_of_m
geniusboy [140]

Answer:

Here is the Python program:

d = {5:3, 4:1, 12:2}

val_of_max = d[max(d.keys())]

print(val_of_max)

Explanation:

The program works as follows:

So we have a dictionary named d which is not empty and has the following key-value pairs:

5:3

4:1

12:2

where 5 , 4 and 12 are the keys and 3, 1 and 2 are the values

As we can see that the largest key is 12. So in order to find the largest key we use max() method which returns the largest key in the dictionary and we also use keys() which returns a view object i.e. the key of dictionary. So

max(d.keys()) as a whole gives 12

Next d[max(d.keys())]  returns the corresponding value of this largest key. The corresponding value is 2 so this entire statement gives 2.

val_of_max = d[max(d.keys())] Thus this complete statement gives 2 and assigns to the val_of_max variable.

Next print(val_of_max) displays 2 on the output screen.

The screenshot of program along with its output is attached.

4 0
2 years ago
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