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2 years ago

^ Casey was able to map line segment UV onto line segment ST using a translation and a rotation.

Mathematics

1 answer:

yarga [219]2 years ago

4 0

Answer:

A. The correct conclusion is that the segments are congruent and similar.

Step-by-step explanation:

Congruent figures are also similar because when all sides are equal, they are in the same ratio too (i.e 1 : 1)

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A coordinate grid with 2 lines. The first line is labeled y equals negative StartFraction 7 over 4 EndFraction x plus StartFract

LekaFEV [45]

Answer:

Question 1. (2.2, -1.4)

Question 2. (1.33, 1)

Step-by-step explanation:

Equations for the given lines are

-----(1)

It is given that this line passes through two points (0, 2.5) and (2.2, 1.4).

------(2)

This equation passes through (0, -3) and (2.2, -1.4).

Now we have to find a common point through which these lines pass or solution of these equations.

From equations (1) and (2),

x =

x = 2.2

From equation (2),

y = -1.4

Therefore, solution of these equations is (2.2, -1.4).

Question 2.

The given equations are y = 1.5x - 1 and y = 1

From these equations,

1 = 1.5x - 1

1.5x = 2

x =

Therefore, the solution of the system of linear equations is (1.33, 1).

5 0

2 years ago

Read 2 more answers

5. You deposit $300 in an account Urat pays 1.48% annual interest. What is the balance after 1 year if the

kirill [66]

Answer:

The correct option is (A) $304.47.

Step-by-step explanation:

The formula to compute the future value (FV) of an amount (A), compounded daily at an interest rate of r%, for a period of n years is:

$FV=A\times [1+\frac{r\%}{365}]^{n\times 365}$

The information provided is:

A = $300

r% = 1.48%

n = 1 year

Compute the future value as follows:

$FV=A\times [1+\frac{r\%}{365}]^{n\times 365}$

$=300\times [1+\frac{0.0148}{365}]^{365}\\\\=300\times (1.00004055)^{365}\\\\=300\times 1.014911\\\\=304.4733\\\\\approx \$304.47$

Thus, the balance after 1 year is $304.47.

The correct option is (A).

8 0

2 years ago

A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The

Oksanka [162]

Answer:

a) $[-0.134,0.034]$

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

$s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2}$ ,

where $n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19$ .

The mean difference $\mu_1 - \mu_2 = 10.85 - 10.90 = -0.05$ .

The confidence interval is

$(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}$

$= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]$

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0

2 years ago

determine 4th term in the geometric sequence whose first term is -2 and whose common ratio is -5. does anyone know what this can

9966 [12]

The terms in a geometric sequence are given by: A = ar^(n-1)
where A is the nth term in the sequence.
a = first term in the sequence (-2)
r = common ratio (-5)
n = number of the term (4)

A = (-2)(-5)^(4-1)
A = (-2)(-5)^(3)
A = (-2)(-125)
A = 250

4 0

2 years ago

How do you solve dy/dx=(y−1)(y+1) if the solution passes through the point (x,y)=(4,0)(x,y)=(4,0)?

OLEGan [10]

Sorry
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6 0

2 years ago