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shepuryov [24]
2 years ago
6

In a recent survey, the proportion of adults who indicated mystery as their favorite type of book was 0.325. Two simulations wil

l be conducted for the sampling distribution of a sample proportion from a population with a true proportion of 0.325. Simulation A will consist of 1,500 trials with a sample size of 100. Simulation B will consist of 2,000 trials with a sample size of 50. Which of the following describes the center and variability of simulation A and simulation B?
A) The centers will roughly be equal, and the variabilities will roughly be equal.
B) The centers will roughly be equal, and the variability of simulation A will be greater than the variability of simulation B.
C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
D) The center of simulation A will be greater than the center of simulation B, and the variability of simulation A will roughly be equal to the variability of simulation B.
E) The center of simulation A will be less than the center of simulation B, and the variability of simulation A will be greater than the variability of simulation B.
Mathematics
1 answer:
Virty [35]2 years ago
3 0

Answer:

C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.

Step-by-step explanation:

The center for Simulation A and Simulation B will be roughly equal.

Overall Sample size of Simulation A = 1500 * 100 = 150000

Overall Sample size of Simulation B = 2000 * 50 = 100000

Since the sample size for Simulation A is greater, the variability of Simulation will be less.

Therefore, The answer is  C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.

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Answer:

0.4007

Step-by-step explanation:

Let's define the following events:

A: method A is used

B: method B is used

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R: the eye is recovered in a month

The probability that the eye has not recovered in a month is 0.002 if method A is used, i.e., P(NR|A) = 0.002, so P(R|A) = 0.998.

When method B is used, the probability that the eye has not recovered in a month is 0.005, i.e., P(NR|B) = 0.005, so P(R|B) = 0.995.

40% of eye surgeries are done with method A, i.e., P(A) = 0.4

60% of eye surgeries are done with method B, i.e., P(B) = 0.6

If an eye is recovered in a month after surgery is done in the hospital, what is the probability that method A was performed? We are looking for P(A|R), then, by Bayes' Formula

P(A|R) = P(R|A)P(A)/(P(R|A)P(A) + P(R|B)P(B)) = 0.998*0.4/(0.998*0.4 + 0.995*0.6) = 0.4007

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