Which change signaled a musical progression toward rock and roll?

5.14 ◆ Write a version of the inner product procedure described in Problem 5.13 that uses 6 × 1 loop unrolling. For x86-64, our

KengaRu [80]

Answer:

(a) the number of times the value is performs is up to four cycles. and as such the integer i is executed up to 5 times. (b)The point version of the floating point can have CPE of 3.00, even when the multiplication operation required is either 4 or 5 clock.

Explanation:

Solution

The two floating point versions can have CPEs of 3.00, even though the multiplication operation demands either 4 or 5 clock cycles by the latency suggests the total number of clock cycles needed to work the actual operation, while issues time to specify the minimum number of cycles between operations.

Now,

sum = sum + udata[i] * vdata[i]

in this case, the value of i performs from 0 to 3.

Thus,

The value of sum is denoted as,

sum = ((((sum + udata[0] * vdata[0])+(udata[1] * vdata[1]))+( udata[2] * vdata[2]))+(udata[3] * vdata[3]))

Thus,

(A)The number of times the value is executed is up to 4 cycle. And the integer i performed up to 5 times.

Thus,

(B) The floating point version can have CPE of 3.00, even though the multiplication operation required either 4 or 5 clock.

3 0

2 years ago

You have been tracking your exercise routine, which involves running, lifting weights, yoga, and stretching. You want to see wha

Harrizon [31]

The best chart to see the data distribution for the exercise routine would be a pie chart. Using Microsoft Excel, you can input each data point you have for all you exercise routine category, and generate a pie chart which will show you the percentage for each category in comparison to the total.

5 0

2 years ago

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Write a public static method named printArray, that takes two arguments. The first argument is an Array of int and the second ar

Serjik [45]

Answer:

Written in Java

public static void printArray(int myarr[], String s){

for(int i = 0; i<myarr.length;i++){

System.out.print(myarr[i]+s);

}

Explanation:

This defines the static method alongside the array and the string variable

public static void printArray(int myarr[], String s){

The following iteration iterates through the elements of the array

for(int i = 0; i<myarr.length;i++){

This line prints each element of the array followed by the string literal

System.out.print(myarr[i]+s);

}

The method can be called from main using:

<em>printArray(myarr,s);</em>

Where myarr and s are local variables of the main

5 0

2 years ago

What is the distance rn between the point of application of n⃗ and the axis of rotation? what is the distance rw between the poi

Mandarinka [93]

Complete Question.

A. Suppose that you are holding a pencil balanced on its point. If you release the pencil and it begins to fall, what will be the angular acceleration when it has an angle of 10.0 degrees from the vertical?

B. What is the distance rn between the point of application of n⃗ and the axis of rotation?

C. What is the distance rw between the point of application of w⃗ and the axis? enter your answers in meters separated by a comma?

Answer:

A. â = - 17rad/s²

B. rn = 0, meters

C. rw = 0.074, meters

Explanation:

Where;

l = length of the pencil

θ = angle between the vertical line and the pencil

â = angular acceleration.

The torque due to weight about the pivotal point is negative since it's clockwise;

t = - mg(l/2)sinØ ..... equation 1

torque with respect to angular acceleration;

t = Iâ ..... equation 2

The moment of Inertia of the pencil about one end;

I = (ml²)/3

Substituting I into equation 2;

t = [(ml²)/3]×â

Equating the equation, we have;

[(ml²)/3]×â = - mg(l/2)sinØ

â = (-3gsinØ)/2l

â = (-3*9.8*sin10°)/(2*0.15)

Angular acceleration, â = -17rad/s²

B. The normal force is acting at the normal force only, so the distance r n between the point of application of n ⃗ and the axis of rotation is zero because the axis of pencil is passing the same point of application w.

C. rn = (lcosØ)/2

rn = (0.15 * cos10°)/2

rn = (0.15 * 0.9848)/2

rn = (0.1477)/2

rn = 0.074m.

Since the gravity acts at exactly half of the length of pencil, distance r w between the point of application of w⃗ and the axis equals 0.074m.

8 0

2 years ago

Write a algorithm to attend birthday party

kolezko [41]

Answer:

2 No

5 14 Yes

Explanation:

8 0

2 years ago

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