X=one type that cost 9
y=one type that cost 8
total books=type1+type2
total books=13
x+y=13
the total cost=cost of each added together
cost of each=number of books times cost per book
total cost=108
9x+8y=108
we have
x+y=13
9x+8y=108
solve for x and y
multiply first equation by -8 and add to first equation
-8x-8y=-104
<u>9x+8y=108 +</u>
x+0y=4
x=4
subsitute
x+y=13
4+y=13
minus 4
y=9
4 of the $9
9 of the $8
thats how to solve
I really want to help but I don’t know the answer, sorry
Please express those fractions properly: 3/4, 7/8.
Let g be the # of gallons the tank could hold when full.
Then (3/4)n + 5 = (7/8)n.
solving for n: Mult all 3 terms by the LCD (8): 6n + 5(8) = 7n.
Then n=5(8) = 40 (gallons). The tank would hold 40 gallons of water were it full.
It would be
.888,7/10,3/5,.27
what you would do is convert 7/10 and 3/5 into a decimal to see what order you would place them and 7/10 as a decimal is .7 and 3/5 to a decimal is .6 so .888 is greater then it will be 7/10 then 3/5 then .27