After deploying a large number of wireless laptop computers on the network, Taylor, the IT director at Contoso, Ltd. decides to
1 answer:
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Solution :
class Employee:
#Define the
#constructor.
def ____(
, ID_number,
, email):
#Set the values of
#the data members of the class.
= name
_number = ID_number
= salary
self.email_address = email
#Define the function
#make_employee_dict().
def make_employee_dict(list_names, list_ID, list_salary, list_email):
#Define the dictionary
#to store the results.
employee_dict = {}
#Store the length
#of the list.
list_len = len(list_ID)
#Run the loop to
#traverse the list.
for i in range(list_len):
#Access the lists to
#get the required details.
name = list_names[i]
id_num = list_ID[i]
salary = list_salary[i]
email = list_email[i]
#Define the employee
#object and store
#it in the dictionary.
employee_dict[id_num] = Employee(name, id_num, salary, email)
#Return the
#resultant dictionary.
return employee_dict
Answer:
- #include <stdio.h>
- int main()
- {
- const double piVal = 3.14159;
- double sphereVolume = 0.0;
- double sphereRadius = 0.0;
- sphereRadius = 1.0;
- sphereVolume = 4.0/ 3.0 * piVal * sphereRadius * sphereRadius * sphereRadius;
- printf("Sphere volume: %lf\n", sphereVolume);
- return 0;
- }
Explanation:
Firstly we can identify the formula to calculate volume of sphere which is
Volume = 4/3
With this formula in mind, we can apply this formula to calculate the volume of sphere in Line 10. This is important to perform floating-point division 4.0/3.0 to ensure the resulting value is a floating value as well. Since we have been given piVal and sphereRadius, we can just multiply the result of floating-point division with piVal and sphereRadius and get the sphereVolume value.
At last, display the sphere volume using printf method (Line 13).