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ivann1987 [24]
2 years ago
12

A square piece of paper has an area of x2 square units. A rectangular strip with a width of 2 units and a length of x units is c

ut off of the square piece of paper. The remaining piece of paper has an area of 120 square units. Which equation can be used to solve for x, the side length of the original square?
Mathematics
1 answer:
lions [1.4K]2 years ago
9 0

Answer: The answer is A. x2 - 2x - 120= 0

Step-by-step explanation:

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If your front lawn is 17.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1050 new snowflakes every minu
Alexus [3.1K]

Answer: 42.84 kg

Step-by-step explanation: Lawn is 17 ft x 20 ft.

Its area is S = 17 x 20 = 340 ft²

Each ft² of lawn accumulates 1050 snowflakes/min, 1ft² = 1050 s.f./min.

As 1 hour has 60 min, the lawn accumulates 63000/hour →

1050 x 60 = 63000

1ft² = 63000s.f./hour

This way, 340 ft² of lawn will accumulate 21,420,000 s.f/hour →

340 x 63000 = 21420000

As 1 snowflake has 2mg,  21,420,000 will have 42,840,000 mg.

As 1kg = 1,000,000 mg

42,840,000/1,000,000 = 42.84 kg

3 0
2 years ago
.580 80 repeating as fraction
denis-greek [22]
First off, we'll move the non-repeating part in the decimal to the left-side, by doing a division by a power of 10.

then we'll equate the value to some variable, and move the repeating part over to the left as well.

anyhow, the idea being, we can just use that variable, say "x" for the repeating bit, let's proceed,

\bf 0.580\overline{80}\implies \boxed{\cfrac{5.80\overline{80}}{10}}\qquad \textit{now, let's say }x= 5.80\overline{80}\\\\
-------------------------------

\bf thus\qquad \begin{array}{llll}
100\cdot x&=&580.80\overline{80}\\
&&575+5.80\overline{80}\\
&&575+x
\end{array}\qquad \implies 100x=575+x
\\\\\\
99x=575\implies x=\cfrac{575}{99}\qquad therefore\qquad \boxed{\cfrac{5.80\overline{80}}{10}}\implies \cfrac{\quad \frac{575}{99}\quad }{10}
\\\\\\
\cfrac{\quad \frac{575}{99}\quad }{\frac{10}{1}}\implies \cfrac{575}{99}\cdot \cfrac{1}{10}\implies \cfrac{575}{990}\implies \stackrel{simplified}{\cfrac{115}{198}}

and you can check that in your calculator.
4 0
2 years ago
Read 2 more answers
A marble is selected at random from a jar containing 3 red​ marbles, 4 yellow​ marbles, and 6 green marbles. What is the probabi
alexgriva [62]

Answer:  a) \dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}

Step-by-step explanation:

Since we have given that

Number of red marbles = 3

Number of yellow marbles = 4

Number of green marbles = 6

Total number of marbles = 3 +4 +6 = 13

​a) the marble is​ red? ​

Probability of getting a red marble = \dfrac{3}{13}

b) the marble is not​ yellow?

Probability of not getting yellow = \dfrac{3+6}{13}=\dfrac{9}{13}

​c) the marble is either red or ​green?

Probability of getting either red or green = P(red) + P(green) =\dfrac{3}{13}+\dfrac{6}{13}=\dfrac{9}{13}

d) the marble is neither red nor ​green?

Probability of getting neither red nor green = P(getting yellow) = \dfrac{4}{13}

Hence, a) \dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}

5 0
2 years ago
How do you Evaluate 3f(2)
kondor19780726 [428]

IT IS TWELVE............ 12

4 0
2 years ago
What is the value of b in the equation (y Superscript b Baseline) Superscript 4 Baseline = StartFraction 1 Over y Superscript 24
shusha [124]

The value of b is -6.

Explanation:

The expression is \left(y^{b}\right)^{4}=\frac{1}{y^{24}}

To determine the value of b, we shall solve the expression.

Applying exponent rule, \left(a^{b}\right)^{c}=a^{b c}, we get,

y^{4b}=\frac{1}{y^{24}}

Applying exponent rule, \frac{1}{a^{b}}=a^{-b}, we have,

y^{4b}=y^{-24}

The expression is of the form, a^{f(x)}=a^{g(x)} then f(x)=g(x)

Applying this rule, we get,

4b=-24

Dividing both sides by 4, we have,

b=-6

Hence, the value of b is -6.

4 0
2 years ago
Read 2 more answers
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