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ivann1987 [24]
2 years ago
12

A square piece of paper has an area of x2 square units. A rectangular strip with a width of 2 units and a length of x units is c

ut off of the square piece of paper. The remaining piece of paper has an area of 120 square units. Which equation can be used to solve for x, the side length of the original square?
Mathematics
1 answer:
lions [1.4K]2 years ago
9 0

Answer: The answer is A. x2 - 2x - 120= 0

Step-by-step explanation:

You might be interested in
In an examination, a candidate has to score 40% marks to pass. Anil scores 22 and failed by 8 marks. What is the full marks?​
alexgriva [62]

Answer:

75

Step-by-step explanation:

Let full marks be x

Then pass marks is 40% of x which is 0.4x

As per given, we have

22= 0.4x - 8

Solving for x

0.4x = 30

x = 30/0.4

x = 75

So full marks is 75

8 0
2 years ago
A bakery sold a total of 3028 coffee buns and blueberry buns. 1560 more coffee buns were sold than the blueberry buns. How many
Natali [406]

Answer:

\large{ \tt{ -  \: HEY  \: AH~\:♡ }}

\large{ \tt{✺ \: SOLUTION}} :

  • Provided : Total sold bakery items : 3028 coffee buns and blueberry buns & 1560 more coffee buns were sold than the blueberry buns.

  • To find : Number of coffee buns the bakery sold

- First , Subtract 1560 from 3028 :

\large{ \tt{→ \: 3028 - 1560 = 1468}}

We just subtacted the number of more coffee buns from the number of told items sold which means that the number of coffee buns and the number of blueberry buns sold are equal for now. Now divide 1428 by 2 :

\large{ \tt{→ \frac{1428}{2} = 734 }}

Now - Let's get back to the second sentence of the question and add 734 & 1560 :

\large{ \tt{→ \: 734 + 1560 =  \large{ \boxed{2294}}}}

  • Hence , The bakery sold 2294 coffee buns.

- Hope this helps , oneesan! ;)

7 0
1 year ago
The number of newly reported crime cases in a county in New York State is shown in the accompanying table, where x represents th
Novay_Z [31]

Answer:

Step-by-step explanation:

I use  84+ CE

stat edit, then fill in the #s

then

vars 5

then

2'nd stat plot, on

then, click stat

Click arrow 1 time to the left to get to Calc

then click (4)(LinReg(ax+b))

then click enter 5 times

(y=-25.31428571x+1000.285714

y=-25.3x+1000.3

now, lets use computer:

y=-25.31(543)+1000.3

y=-12743.03

round to the biggest whole number )

this doesn't really work, so I will put 1999, 2000, 2001, 2002, 2003, 2004 instead of 0, 1, 2, 3, 4, 5 and do the same thing

now I get

y=-25.31428571x+51603.54286

y=-25.3x+51603.5

now, lets use computer:

y=-25.3(543)+51603.5

y=37865.6

round to the biggest whole number:

y=37866

so, year 37866

7 0
2 years ago
In a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979,
Fed [463]

Answer:

we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

Step-by-step explanation:

Given that in a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979, two groups of childless wives aged 25 to 29 were selected at random, and each was asked if she eventually planned to have a child. One group was selected from among wives married less than two years and the other from among wives married five years.

Let X be the group married less than 2 years and Y less than 5 years

                         X        Y     Total

Sample size   300   300    600

Favouring       240   288    528

p                      0.8     0.96  0.88

H_0: p_x=p_y\\H_a: p_x>p_y

p difference = -0.16

Std error for difference = \sqrt{0.88*0.12/600} =0.01327

Test statistic = p difference/std error=-6.03

p value <0.000001

Since p is less than alpha 0.05 we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

4 0
2 years ago
According to a "how to stop bullying" Web site, 15% of students report experiencing bullying one to three times within the most
AlekseyPX

Answer:

His 95% confidence interval is (0.065, 0.155).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 186, \pi = 0.11

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 - 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.065

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 + 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.155

His 95% confidence interval is (0.065, 0.155).

4 0
1 year ago
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