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Ulleksa [173]
2 years ago
7

A bag of potatoes weights 30 lb. If 74% of a potato is water, how many pounds of water are there in the bag?

Mathematics
1 answer:
Nadya [2.5K]2 years ago
3 0

Answer: There are 22.2 pounds of water in the bag.

Step-by-step explanation:

Hi, to answer this question we simply have to multiply the total weight of the bag by the water percentage in decimal form (divided by 100).

Mathematically speaking:

30 x (74/100) = 30 x 0.74 =22.2 pounds

There are 22.2 pounds of water in the bag.

Feel free to ask for more if needed or if you did not understand something.

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Which number line correctly shows 4.5 – 2.5? A number line going from 0 to 4.5 in increments of 0.5. An arrow goes from 0 to 4.5
NemiM [27]

Answer:

A number line going from 0 to 4.5 in increments of 0.5

Step-by-step explanation:

This solution makes the most sense because 4.5 and 2.5 both have a decimal of 0.5

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2 years ago
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The ice cream shop has 80 different possible sundaes which include 1 flavor of ice cream, 1 syrup, and 1 candy topping. If the i
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It should be 4 according to my stats
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2 years ago
this squared based pyramid is cut horizontally at a height of 15cm to leave this frustum base area=10cm
scoundrel [369]

Answer:

583.33 cm³

Step-by-step explanation:

From the image attached, the total height (H) of the pyramid is 30 cm, the height of the frustrum (h) = 15 cm, the Frustrum base = lower base = B = 10 cm . To find the length of the upper base (b), we use:

\frac{b}{H-h}=\frac{B}{H}\\  b=(H-h)\frac{B}{H}\\b=(30-15)\frac{10}{30}=5\\b=5\ cm

The volume of the frustrum is given by:

V=\frac{1}{3}h(B_1+B_2+\sqrt{B_1B_2} )\\ Where\ B_1\ is \ the\ area \ of\ the\ upper\ base= 5cm*5cm=25cm^2\\B_1\ is \ the\ area \ of\ the\ lower\ base= 10cm*10cm=100cm^2\\V=\frac{1}{3}(10)(25+100+\sqrt{25*100} )=583.33\\V=583.33\ cm^3

6 0
2 years ago
The line 3y+x=25 is a normal to the curve y=x2-5x+k.find the value of constant k.
ladessa [460]

Answer:

k = 11.

Step-by-step explanation:

y = x^2 - 5x + k

dy/dx = 2x - 5 = the slope of the tangent to the curve

The slope of the normal = -1/(2x - 5)

The line  3y + x =25 is normal to the curve so finding its slope:

3y = 25 - x

y = -1/3 x + 25/3 <------- Slope is -1/3

So at the point of intersection with the curve, if the line is normal to the curve:

-1/3 = -1 / (2x - 5)

2x - 5 = 3  giving x = 4.

Substituting for x in y = x^2 - 5x + k:

When x = 4, y =  (4)^2 - 5*4 + k  

y = 16 - 20 + k

so y = k - 4.

From the equation y = -1/3 x + 25/3,  at x = 4

y = (-1/3)*4 + 25/3 = 21/3 = 7.

So y = k - 4 = 7

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Answer:

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