Suppose that the exam scores for students in a large university course are normally distributed with an unknown mean and standar
d deviation. The scores of 42 randomly sampled students in the course are used to estimate the mean of the population. What t-score should be used to find the 99% confidence interval for the population mean? df...4041424344t0.10…1.3031.3031.3021.3021.301t0.05…1.6841.6831.6821.6811.680t0.025…2.0212.0202.0182.0172.015t0.01…2.4232.4212.4182.4162.414t0.005…2.7042.7012.6982.6952.692 Use the portion of the table above or a calculator. If you use a calculator, round your answer to three decimal places.
1 answer:
Answer:
Critical value t-score=2.701.
Step-by-step explanation:
When we calculate a confidence interval with an unknown population standard deviation, we estimate it from the sample standard deviation and use the t-score instead of the z-score.
The critical value for t depends on the level of confidence and the degrees of freedom.
If the sample size is 42, the degrees of freedom are:
For a confidence level of 99% and 41 degrees of freedom, the critical value of t is t=2.701.
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<span>A geometric sequence is a sequence of
numbers where each term after the first is found by multiplying the
previous one by a fixed, non-zero number called the common ratio.
</span>The common ration is obtained by dividing the a term by the preceding term.
Given that f<span>our students wrote sequences during math class with
Andre writing
Brenda writing </span>
Camille writing
Doug writing
Notice that the common ratio for the four students is
.
For Andre, the last term is wrong and hence his sequence is not a geometric sequence.
For Brenda, the last term is wrong and hence her sequence is not a geometric sequence.
For Camille, her sequence is not a geometric sequence.
For Doug, his sequence is a geometric sequence with a common ratio of.
Therefore, Doug wrote a geometric sequence.
</span>The common ration is obtained by dividing the a term by the preceding term.
Given that f<span>our students wrote sequences during math class with
Andre writing
Brenda writing </span>
Camille writing
Doug writing
Notice that the common ratio for the four students is
For Andre, the last term is wrong and hence his sequence is not a geometric sequence.
For Brenda, the last term is wrong and hence her sequence is not a geometric sequence.
For Camille, her sequence is not a geometric sequence.
For Doug, his sequence is a geometric sequence with a common ratio of
Therefore, Doug wrote a geometric sequence.