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Elena-2011 [213]

2 years ago

4

The total number of students enrolled in MATH 123 this semester is 6,072. If it decreases by 0.89% for the next semester, what w

ill be the enrollment next semester? Round to a whole person.

1 answer:

Lunna [17]2 years ago

7 0

Answer:

About 6,018 students

Step-by-Step Explanation:

0.0089 x 6,072 = 54.0408

6,072 - 54.0408 = 6017.9592

6017.9592 can be rounded to 6,018

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Select the correct answer. Gary throws a parachute toy from the roof of a building which has a height of 96 feet. The toy reache

Artyom0805 [142]

Answer:

Z

Step-by-step explanation:

The height needs to start at 96

8 0

2 years ago

you own a pet supply store, and the total sales in your trading area equal 27,000. Your market share is 45%. What were your sale

Mazyrski [523]

Answer:

The sales is Rs. 12150.

Step-by-step explanation:

Given : You own a pet supply store, and the total sales in your trading area equal 27,000. Your market share is 45%.

To find : What were your sales ?

Solution :

Total sales = 27,000

Market share = 45%

Sales is given by,

Sales is 45% of total sale.

So, $S=27000\times \frac{45}{100}$

$S=12150$

Therefore, the sales is Rs. 12150.

6 0

2 years ago

Read 2 more answers

f1(x) = ex, f2(x) = e−x, f3(x) = sinh(x) g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, and c3 so that g(x) = 0 on the int

eimsori [14]

Answer:

(C1, C2, C3) = (K, K, -2K)

For K in the interval (-∞, ∞)

Step-by-step explanation:

Given

f1(x) = e^x

f2(x) = e^(-x)

f3(x) = sinh(x)

g(x) = 0

We want to solve for C1, C2 and C3, such that

C1f1(x) + C2f2(x) + C3f3(x) = g(x)

That is

C1e^x + C2e^(-x) + C3sinh(x) = 0

The hyperbolic sine of x, sinh(x), can be written in its exponential form as

sinh(x) = (1/2)(e^x + e^(-x))

So, we can rewrite

C1e^x + C2e^(-x) + C3sinh(x) = 0

as

C1e^x + C2e^(-x) + C3(1/2)(e^x + e^(-x)) = 0

So we have

(C1 + (1/2)C3)e^x + (C2 + (1/2)C3)e^(-x) = 0

We know that

e^x ≠ 0, and e^(-x) ≠ 0

So we must have

(C1 + (1/2)C3) = 0...........................(1)

and

(C2 + (1/2)C3) = 0..........................(2)

From (1)

2C1 + C3 = 0

=> C3 = -2C1.................................(3)

From (2)

2C2 + C3 = 0

=> C3 = -2C2................................(4)

Comparing (3) and (4)

2C1 = 2C2

=> C2 = C1

Let C1 = C2 = K

C3 = -2K

(C1, C2, C3) = (K, K, -2K)

For K in the interval (-∞, ∞)

3 0

2 years ago

The cost, c(x), for a taxi ride is given by c(x) = 3x + 2.00, where x is the number of minutes. What does the slope mean for thi

xxTIMURxx [149]

Simple...

you have: C(X)=3x+2.00

x=number of minutes

Pay attention to the y=mx+b form where m=slope-->>

3x is the slope...

so it's 3(times the number of minutes) <<---or (x)

This means that the slope is 3, or the fancy way of saying it-->>"rate of change."

The rate of change of the cost of the taxi ride is $3.00 per minute.

Thus, your answer.

7 0

2 years ago

Bonzo went to a carnival. At the first

Shalnov [3]

Bonzo started with 2.1 dollars

Step-by-step explanation:

Assume that Bonzo has $x

1. Change $x to cents

2. Calculate the remaining money with him after each game

3. Equate the left money in the 3rd game by zero to find x

∵ $1 = 100 cents

∴ $x = 100 x cents

First game

∵ Bonzo has 100 x cents

∵ He paid 10¢ to get in

∴ The money left is (100 x - 10)

∵ He spent half the money he had left

- That mean the money left with him is the other have

∴ The money left with him = $\frac{1}{2}$ (100 x - 10) = (50 x - 5) cents

∵ He spent 10¢ to get out

∴ The money left after 1st game = (50 x - 5) - 10

∴ The money left after 1st game = (50 x - 15) cents

Second game

∵ Bonzo has (50 x - 15) cents

∵ He paid 10¢ to get in

∴ The money left is (50 x - 15) - 10 = (50 x - 25)

∵ He spent half the money he had left

∴ The money left with him = $\frac{1}{2}$ (50 x - 25) = (25 x - 12.5) cents

∵ He spent 10¢ to get out

∴ The money left after 2nd game = (25 x - 12.5) - 10

∴ The money left after 2nd game = (25 x - 22.5) cents

Third game

∵ Bonzo has (25 x - 22.5) cents

∵ He paid 10¢ to get in

∴ The money left is (25 x - 22.5) - 10 = (25 x - 32.5)

∵ He spent half the money he had left

∴ The money left with him = $\frac{1}{2}$ (25 x - 32.5) = (12.5 x - 16.25) cents

∵ He spent 10¢ to get out

∴ The money left after 3rd game = (12.5 x - 16.25) - 10

∴ The money left after 3rd game = (12.5 x - 26.25) cents

∵ He found he had no money left after the 3rd game

∴ Equate the left money with him by zero

∴ 12.5 x - 26.25 = 0

- Add 26.25 to both sides

∴ 12.5 x = 26.25

- Divide both sides by 12.5

∴ x = 2.1

<em>Bonzo started with 2.1 dollars </em>

Learn more:

You can learn more about money in brainly.com/question/1870710

#LearnwithBrainly

5 0

2 years ago