Provided that there's no diagram, most molecules have particular areas on the molecules, called the "active area" that act as a lock to a particular substrate's molecular structure, providing the key.
An enzyme's active area is only able to be "unlocked" by a certain substrate's "key".
Answer:
The carrying capacity of a wildlife reserve is 570 individuals for a particular species of rodents. If the area of the reserve is extended, the carrying capacity is likely to Increase
During the summer, a fatal disease began killing individuals. The carrying
capacity of the reserve will therefore decrease
Explanation:
The carrying capacity of a habitat is the maximum number of individuals of a given species it can support without depleting the available resources. When the area of the reserve is extended, the carrying capacity increases because the available resources will also increase. A fatal disease would increase the carrying capacity since the number of wildlife would decrease.
The traits an organism displays are ultimately determined by the genes it inherited from its parents, in other words by its genotype. Animals have two copies of all their chromosomes, one from each parent
Answer:
Cross each to a rabbit who you know is homozygous - i.e. a white rabbit. If there are any white offspring you know this is the heterozygote.
Explanation:
Heterozygous individuals are those with 2 different alleles of a gene. Homozygous individuals have have 2 alleles that are the same.
Imagine the allele for coat color is B black, or b white. If you cross 2 individuals who are homozygous for the black gene (BB), they would only produce black rabbits in the F1 (BB). If you cross the F1, they could only produce BB rabbits in the F2.
However, if you cross a heterozygous rabbit with a homozygous black rabbit (Bb x BB), you would get either BB or Bb rabbits in the F1. However, intercrossing them could produce BB, Bb, or bb rabbits. Therefore, white rabbits can be produced.
You know that white rabbits are bb. So if you are unsure about the genotype of the black rabbit, you can cross it with a white rabbit (either BB x bb or Bb x bb). If any white rabbits appear in the F1, you know there must be a b allele in the black rabbit genotype, so that rabbit must be heterozygous.
E translocation is the answer