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N76 [4]
2 years ago
7

Suppose the following regression equation was generated from the sample data of 50 cities relating number of cigarette packs sol

d per 1000 residents in one week to tax in dollars on one pack of cigarettes and if smoking is allowed in bars:
PACKS i= 57221.431732 − 1423.696906TAXi + 155.441784BARSi + ei.
BARS i= 1 if city i allows smoking in bars and BARSi = 0 if city i does not allow smoking in bars. This equation has an R2 value of 0.351292, and the coefficient of BARSi has a P-value of 0.086529. Which of the following conclusions is valid?
A. According to the regression equation, regardless of whether or not smoking is allowed in bars, the number of cigarette packs sold per 1000 people decreases by approximately 1424 for each additional dollar of cigarette tax.
B. There is evidence at the 0.05 level of significance to support the claim that cities with a smoking ban have lower cigarette sales than those without a smoking ban.
C. According to the regression equation, cities that allow smoking in bars have lower cigarette sales than cities that do not allow smoking in bars.
D. According to the regression equation, cities that allow smoking in bars sell approximately 155 fewer packs of cigarettes per 1000 people than cities that do not allow smoking in bars.
Mathematics
1 answer:
frez [133]2 years ago
4 0

Answer:

A) According to the regression equation, regardless of whether or not smoking is allowed in bars, the number of cigarette packs sold per 1000 people decreases by approximately 1424 for each additional dollar of cigarette tax.

Step-by-step explanation:

Given the regression equation:

PACKS i= 57221.431732 − 1423.696906TAXi + 155.441784BARSi + eᵢ.

BARS i= 1 if city i allows smoking in bars

BARSi = 0 if city i does not allow smoking in bars

R2 = 0.351292

P-value = 0.086529

Conlusion:

Simnce p value, 0.0865 is greater than level of significance, 0.05, BARS is not significant. Thus, allowing smoking in bars increase cigarette sales, since the coefficient of BARS is positive.

Correct answer is option A.

According to the regression equation, regardless of whether or not smoking is allowed in bars, the number of cigarette packs sold per 1000 people decreases by approximately 1424 for each additional dollar of cigarette tax.

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A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical
Korolek [52]

Answer:

78% probability that a randomly selected online customer does not live within 50 miles of a physical​ store.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Total outcomes:

100 customers

Desired outcomes:

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.

Using this​ estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical​ store?

p = \frac{78}{100} = 0.78

78% probability that a randomly selected online customer does not live within 50 miles of a physical​ store.

4 0
2 years ago
Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes
Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2\times 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 \times 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled \triangle AOB.

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = \dfrac{Total\ distance}{Total\ time}

\Rightarrow \dfrac{74.28}{5} = 14.86\ knots

6 0
2 years ago
There is a harvest festival each year on the planet Bozone. During that time, most of the Bozone residents sit down to rejoice a
Oliga [24]

Answer:

The price would be decreased by 18 bozats

Step-by-step explanation:

The following information is given in the question

x = number of kilograms of snig sold

P = Price per kilogram

And, the equation is

p = 300 - 18x

Now if an extra kilogram is sold so it should be x+1

Now the new price is

New price = 300 - 18(x + 1)

= 300 - 18x - 18

Therefore the price would be decreased by 18 bozats

8 0
2 years ago
Read 2 more answers
Dividends Per Share Seventy-Two Inc., a developer of radiology equipment, has stock outstanding as follows: 60,000 shares of cum
anygoal [31]

Answer and Step-by-step explanation:

The computation of dividends per share on each class of stock for each of the four years is shown below:-

Particulars                1st year     2nd-year     3rd-year     4th year

Preferred dividend

paid a                         $34,000   $38,000    $36,000    $36,000

Number of preferred

stock b                       60,000     60,000       60,000       60,000

Dividend per share

(a ÷ b)                         $0.57       $0.63          $0.60             $0.60

Dividend paid to common

stockholders c               $0             $38,000    $44,000     $64,000

Number of common stock

shares d                       410,000     410,000     410,000     410,000

Dividend per share

on common stock        $0             $0.093        $0.11          $0.16

(c ÷ d)

Working note:

Preferred dividend = Number of preferred stock shares × Par value per share × Percentage of dividend

= 60,000 × $20 × 3%

= $36,000

Preferred stock

For 1st year

= $34,000

For 2nd-year

Dividend in year 2+ Dividend balance in year 1

= $36,000 + ($36,000 - $34,000)

= $38,000

For 3rd-year

= $36,000

For 4th year

= $36,000

Common stock dividend

Particulars                      1 year        2 year       3 year       4 year

Total dividend paid       $34,000  $76,000   $80,000     $100,000

Less:

Preferred stock

dividend                      $34,000      $38,000  $36,000     $36,000

Dividend paid to common

stockholders                 $0             $38,000    $44,000     $64,000

8 0
2 years ago
One column of numbers consists of 61, 24, and 47. When the digits of the numbers are added together, the result is 6 + 1 + 2 + 4
ololo11 [35]
The question is incomplete because it must content a list of choices to select the right one.

Any way, a conclusion that you can make, and that is a common one for this kind of questions, is about whether the sum of the numbers of the second column may or not be the same sum of the numbers of the first column.

The condition for the two sums be the same is that when the digits of the second column are added together the result be the same obtained for the sum of the digits of the first column. In this case that is 6.

So, the possible answer is:

<span>If the end result from the second column is not 6, then the sum of the numbers in the first column is not equal to the sum of the numbers in the second column.</span>
5 0
2 years ago
Read 2 more answers
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