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Elena-2011 [213]
2 years ago
3

12/31/2019: At the end of the first year of operations, Yolandi Company had $900,000 in sales and accounts receivable of $350,00

0. XYZ's management has estimated that $9,000 in accounts receivable would be uncollectible.
Mathematics
1 answer:
vredina [299]2 years ago
8 0

Answer:

The journal entry to record bad debt expense should be:

December 31, 2019, bad debt expense

Dr Bad debt expense 9,000

    Cr Allowance for doubtful accounts 9,000

Net account receivables = $350,000 - $9,000 = $341,000

The allowance for doubtful accounts is a contra asset account that decreases the balance of accounts receivable (balance sheet). Bad debt expense is included in the income expenses and decreases total sales.

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Serhud [2]
Your answer would be B because even though it's the same shape the red shape is 2 times bigger.......your exponent 4 stays 4
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Complete the area model representing the polynomial x2 − 11x + 28. What is the factored form of the polynomial? Use the model to
qwelly [4]

Answer:

\boxed{\sf  \ \ \ (x-4)(x-7) \ \ \ }

Step-by-step explanation:

Hello,

from the expression we can say that the sum of the two zeroes is 11 and the product is 28

4 + 7 = 11

4 * 7 = 28

so we can write

x^2-11x+28=(x-4)(x-7)

hope this helps

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When you are out in the sunshine you feel warm because the _____ energy excites the molecules of your skin and creates heat ther
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The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.
Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

h(t)=-16t^2+80t+64

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A)  Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

-16t^2+80t+64=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+80t+64=0

so

a=-16\\b=80\\c=64

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}

t=\frac{-80\pm\sqrt{10,496}} {-32}

t=\frac{-80+\sqrt{10,496}} {-32}=-0.70

t=\frac{-80-\sqrt{10,496}} {-32}=5.70

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

-16t^2+80t+64=40

-16t^2+80t+24=0

Solve the quadratic equation

we have

a=-16\\b=80\\c=24

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}

t=\frac{-80\pm\sqrt{7,936}} {-32}

t=\frac{-80+\sqrt{7,936}} {-32}=-0.28

t=\frac{-80-\sqrt{7,936}} {-32}=5.28

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0
2 years ago
Multiply.<br><br> [−12⋅47]⋅[−14⋅(−0.1)]<br><br> What is the product?
yan [13]

Answer:

-789.6

Step-by-step explanation:

I don't know if this is right

8 0
1 year ago
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