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2 years ago

*31. Priya and Ravish planned to participate in a cycle race to be organised for National integration. They decided

Mathematics

1 answer:

Julli [10]2 years ago

7 0

Answer:

36 minutes

2 rounds for Priya

3 rounds for Ravish

Step-by-step explanation:

The answer is the LCM (least common multiple) of 12 and 18.

12 = 2^2 x 3

18 = 3^2 x 2

=>LCM of 12 and 18 = 2^2 x 3^2 = 4 x 9 = 36

=> After 36 minutes they meet again at the starting point

=> At that time, Priya has completed: 36/18 = 2 rounds

=> At that time, Ravish has completed: 36/12 = 3 rounds

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Anita had $400 in her savings account when she went to college. Her parents will add $200 to her account each month. Miguel had

lesantik [10]

At first, Anita looks like her account would grow faster. By month 4, shes at $1,200 while Miguel is at $400. However, Anita is only getting $200 a month. While Miguel gets double of whatever amount he has in his bank account. By month 10, Anita is at $2,400 while Miguel has $25,600. That is a $23,200 difference. So Miguel's bank account will grow faster than Anita.

5 0

2 years ago

If quadrilateral PQRS is a rectangle, then which of the following is true?

brilliants [131]

∠STP ≅ ∠QTR is the True statement ⇒ answer C

Step-by-step explanation:

In any rectangle

1. Each two opposite sides are equal and parallel

2. The measure of its vertex angles is 90°

3. The two diagonals are equal

Now lets find the true statements

∵ PQRS is a rectangle

∴ PS = QR ⇒ opposite sides

∴ PQ = SR ⇒ opposite sides

∴ PR = QS ⇒ diagonals

A. ∠PSQ ≅ ∠QSR

∵ The diagonals of the rectangle do not bisect the vertex angles

∴ AQ does not bisect angle S

∴ m∠PSQ ≠ m∠QSR

∴ ∠PSQ not congruent ∠QSR

∠PSQ ≅ ∠QSR ⇒ False

B. segment SR ≅ segment RQ

∵ SR and RQ are two adjacent sides

∵ The adjacent side in the rectangle not equal

∴ SR ≠ QR

∴ segment SR not congruent to segment RQ

segment SR ≅ segment RQ ⇒ False

C. ∠STP ≅ ∠QTR

∵ PR intersects QS at point T

∴ m∠STP = m∠QTR ⇒ vertically opposite angles

∴ ∠STP ≅ ∠QTR

∠STP ≅ ∠QTR ⇒ True

D. segment PS ≅ segment PR

∵ PS is a side in the rectangle

∵ PR is a diagonal in the rectangle

∵ The side of the rectangle not equal the diagonal of the rectangle

∴ PS ≠ PR

∴ segment PS not congruent to segment PR

segment PS ≅ segment PR ⇒ False

∠STP ≅ ∠QTR is the True statement

Learn more:

You can learn more about rectangle in brainly.com/question/6594923

#LearnwithBrainly

8 0

2 years ago

Read 2 more answers

Tan 235° = 2tan20°+ tan215°

Mariulka [41]

Given : tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20 = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20 = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20 = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20 = (Tan 55 - Tan 35) /2

=> 2 Tan 20 = Tan 55 - Tan 35

=> 2 Tan 20 + Tan 35 = Tan 55

=> tan 55 = 2tan 20 + tan 35

=> tan 235 = 2tan 20 + tan 215

QED

Hence Proved

5 0

1 year ago

If 40% of a number is 32, what is 25% of that number?

Mekhanik [1.2K]

Well what I would do is split the 40% into 20% so from 40% to 20% that is /2. So 32/2=16 so 20% of a number is 16, we know there is 5, 20% in 100% so multiply 16 and 5 which gives you 80. Now 25% of 80 is the same as 80*.25 or 80/4 which is 20

Your Answer 20

7 0

2 years ago

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The angle measures associated with which set of ordered pairs share the same reference angle

Trava [24]

Answer:

Option 3 is right.

Step-by-step explanation:

Reference angle of x is obtained by either 180-x, 180+x. or 360-x depending on the posiiton of terminal whether II quadrant or iv quadrant, or iii quadrant, etc.

In whatever way we find reference angles,

cos will remain cos only and sin will remain sin only there may be only changes in sign.

Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos. Hence these options cannot be for reference angles.

III option is $(-\frac{1}{2} ,\frac{-\sqrt{3} }{2} )(\frac{1}{2} ,\frac{\sqrt{3} }{2} )$

show that both sign and cos changed sign. This is possible only in III quadrant.

ie reference angle of orignal angle t = 180+t

SO this option is right.

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2 years ago

Read 2 more answers