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DanielleElmas [232]
2 years ago
13

Solve the literal equation for y. -12x-3y=15

Mathematics
2 answers:
expeople1 [14]2 years ago
4 0
-12x-3y=15\ \ \ |add\ 12x\ to\ both\ sides\\\\-12x+12x-3y=15+12x\\\\-3y=12x+15\ \ \ |divide\ both\ sides\ by\ (-3)\\\\-3y:(-3)=12x:(-3)+15:(-3)\\\\\huge\boxed{y=-4x-5}
Studentka2010 [4]2 years ago
3 0

You said that                             -12x - 3y  =  15

Add  3y  to each side:               -12x         =  15 + 3y

Subtract  15  from each side:   -12x - 15   =          3y

Divide each side by  3 :            -  4x - 5    =            y  

You might be interested in
Triangle A has a height of 2.5\text{ cm}2.5 cm2, point, 5, start text, space, c, m, end text and a base of 1.6\text{ cm}1.6 cm1,
konstantin123 [22]

Answer:

Option A

Option D

Option E

Step-by-step explanation:

we know that

If the height and base of triangle B are proportional to the height and base of triangle A

then

Triangle A and Triangle B are similar

Remember that

If two triangles are similar then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

\frac{h_A}{h_B} =\frac{b_A}{b_B}

where

h_A and h_B are the height of triangle A and triangle B

b_A and b_B are the base of triangle A and triangle B

In his problem we have

h_A=2.5\ cm\\b_A=1.6\ cm

substitute

\frac{2.5}{h_B} =\frac{1.6}{b_B}

Rewrite

\frac{2.5}{1.6} =\frac{h_B}{b_B}

\frac{h_B}{b_B}=1.5625

<u><em>Verify all the options</em></u>

A) we have

h_B=2.75\ cm\\b_B=1.76\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{2.75}{1.76}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

B) we have

h_B=9.25\ cm\\b_B=9.16\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{9.25}{9.16}=1.0098

The ratios are not equal

That means that are not proportional

therefore

These values could not be the height and base of triangle B

C) we have

h_B=3.2\ cm\\b_B=5\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{3.2}{5}=0.64

The ratios are not the same

That means that are not proportional

therefore

These values could not be the height and base of triangle B

D) we have

h_B=1.25\ cm\\b_B=0.8\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{1.25}{0.8}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

E) we have

h_B=2\ cm\\b_B=1.28\ cm

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

\frac{2}{1.28}=1.5625

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

8 0
2 years ago
The figure below shows a parallelogram ABCD. Side AB is parallel to side DC and side AD is parallel to side BC: A quadrilateral
il63 [147K]
The postulate that is used in order to prove the congruency of the triangles is the ASA which means (Angle – Side – Angle). The property that is applicable for the congruency of DB to itself is the reflexive property. Therefore, the answer to this item is the second choice. 
 Hope I helped! :)
6 0
2 years ago
Read 2 more answers
Mr. Anderson drove 168 miles in 3.5 hours. He then drove the next 2.25 hours at a rate of 5 miles an hour faster than the first
SVEN [57.7K]
  1. Mr. Anderson drove 168 miles in 3.5 hours. Distance here is 168 miles.
  2. He drove for 2.25 at a rate of 5miles/hour. The speed here is 5miles/hour.

Since we are looking for distance, we have to convert the 2nd part (which is the speed) to dostance.

Distance = speed x time

Distance = 5 x 2.25 = 11.25

In the first part, he drove for 3.5 hours. And in the 2nd part, he drove for 2.25 hours which sum up together to be 5.75 hours.

Since we have the distances for both parts now, we just sum it up

which it 168 + 11.25 = 179.25 miles

I hope this is good

4 0
2 years ago
Pete took a sample of moviegoers to see how many are seeing a comedy. Sample size: 175 Number seeing a comedy: 42 Population: 1,
Anastaziya [24]

Answer: Part A : c = n.p

Part B = 366 moviegoers

Step-by-step explanation: In part A, to predict the number of moviegoers, we have to find the <u>proportion</u> of the sample that does the activity, which will called <u>p</u>. Since <u>p</u> is a percentage, to determine how many moviegoers are seeing a comedy, you multiply it by the sample size, <u>n</u>.

Therefore: c = n.p

For part B, based on the the sample:

p = \frac{42}{175} = 0.24

The total population is given: 1,525

c = 0.24.1,525

c = 366

Based on the sample, <u>366</u> <u>people</u> are seeing a comedy.

3 0
2 years ago
Mark sold 2 7/8 gallons of lemonade. Regan sold 2/3 as much as Mark. How much did Regan sold in gallons? can you solve it step b
adelina 88 [10]

Answer:

Step-by-step explanation:

The phrase "twice as much lemonade" tells you that if Mark sold 2 gallons and Regan sold twice as much as Mark, then Regan sold 2 * 2 which is 4 gallons, right?  It's the same with the "2/3 as much".  But since 2/3 is less than 1, the amount after you multiply some number by 2/3 is going to be less than the original number.  

If Mark sold 2 7/8 gallons and Regan sold 2/3 as much, then Regan sold

2\frac{7}{8}*\frac{2}{3}

I teach my algebra students to change that mixed fraction into an improper to make the multiplication easier:

\frac{23}{8}*\frac{2}{3}=\frac{46}{24}=\frac{23}{12}=1\frac{11}{12}

0 0
2 years ago
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