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2 years ago

The distance between Singapore and Sydney is 6300 km correct to the nearest 100 km

Mathematics

1 answer:

Yuri [45]2 years ago

8 0

Answer:

Step-by-step explanation:

If the distance between Singapore and Sydney is 6300 km correct to the nearest 100 km, it means that the actual distance could have been at least 6250 km. If the businessman travelled from Singapore to Sydney and then back to Singapore for six times in a year, it means that he covered each distance 12 times(6 × 2) Then, his total distance would be between

6250 × 12 = 75000 km

And

6300 × 12 = 75600 km

The limit is between 75000 km and 75600 km

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It takes Evan 6 3/4 hours to mow 3 lawns. it takes him 2 1/3 hours to mow Mr. Smiths yard and 1 3/4 hours to mow Ms. Lee's yard.

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Answer: $2\frac{2}{3}\ hours$

Step-by-step explanation:

Given: The total time taken by Evan to mow the 3 lawns = $6\frac{3}{4}=\frac{27}{4}\ \text{hours}$

Time taken by Evan to mow the first lawn = $2\frac{1}{3}=\frac{7}{3}\ \text{hours}$

Time taken by Evan to mow the second lawn = $1\frac{3}{4}=\frac{7}{4}\ \text{hours}$

Now,Time taken by Evan to mow the third lawn = $\frac{27}{4}-\frac{7}{3}-\frac{7}{4}$

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Hence, the time taken by Evan to mow the third lawn = $2\frac{2}{3}\ hours$

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2 years ago

The table shows the progress of a plant's growth. The height of the plant, y, is given by the table, where x is the number of da

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Answer:

The table shows the progress of a plant's growth. The height of the plant, y, is given by the table, where x is the number of days.

Which statements are correct?

The rate of change is 2 cm.

The plant's height at 10 days is 30 cm.

The plant's height at 30 days is 40 cm.

The initial height of the plant is 0 centimeters high.

Step-by-step explanation:

The plant's growth can be modeled by the equation y-2x+10.

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At a college, 72% of courses have final exams and 46% of courses require research papers. Suppose that 31% of courses have a res

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Answer:

0.25

Step-by-step explanation:

72% of courses have final exams and 46% of courses require research papers which means probability of 0.72 for courses that have final exams and 0.46 for courses that require research papers.

31% of courses have a research paper and a final exam, which means probability of 0.31 for both courses with exams and research papers, using Venn diagram approach, find picture attached to the solution.

P(R or E) = P(R) + P(E) - P(R and E), which gives:

P(R or E) = 0.15 + 0.41 - 0.31

P(R or E) = 0.25.

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