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1 year ago

Find the similarity ratio of a cube with a surface area of 36 m² to a cube with a

Mathematics

2 answers:

melisa1 [442]1 year ago

6 0

Answer:

4.9

Step-by-step explanation:

likoan [24]1 year ago

6 0

Answer:

yo need to imply the m^2 into bolth equations

Step-by-step explanation:

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The base of the isosceles triangle is parallel to x-axis and has both end-points on the parabola y=x(10−x) and its vertex belong

baherus [9]

Answer:

Step-by-step explanation:

We must determine the x and y intercepts of the parabola:

When y=0, x=0 or x=10

WE know that the point of the triangle base is x and x+8. We can substitute this into the parabola equation because the endpoints are on the parabola.

f(x+8) $=-(x^2+16x+64)+10x+80$

f(x+8) $=-x^2-6x+16$

f(x)=f(x+8)

$-x^2+10x=-x^2-6x+16$

solve for x

$16x=16$

$x=1$

Therefore the heigh is f(1):

$=-1^2+10=9$

The area of the triangle is 1/2 base x height:

$=(1/2)\cdot{8}\cdot{9}=36$

6 0

2 years ago

Hallie can use the equation p = 4l + 4w + 4h to determine the sum of the lengths of the edges of a rectangular prism. She begins

AfilCa [17]

Answer:

h = p - l - w

Step-by-step explanation:

p = 4l + 4w + 4h Divide l, w, and h by 4

p = l + w + h Set the equation equal to h

h = p - l - w

5 0

1 year ago

Read 2 more answers

A psychologist would like to examine the effects of different testing methods on the final performance of college students. One

lawyer [7]

Answer:

Check the explanation

Step-by-step explanation:

One way ANOVA

The null and alternative hypothesis for this one way ANOVA is given as below:

Null hypothesis: H0: There is no significant difference in the averages of the scores for the quizzes, exams and final only.

Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.

The ANOVA table with calculations can be seen in the attached images below:

In the attached image below, we get the p-value for this one way ANOVA test as 0.0221. We do not reject the null hypothesis if the p-value is greater than the given level of significance and we reject the null hypothesis if the p-value is less than the given level of significance or alpha value.

In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.