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4vir4ik [10]
1 year ago
6

(Displaying a Sentence with Its Words Reversed) Write an application that inputs a line of text, tokenizes the line with String

method split and outputs the tokens in reverse order. Use space characters as delimiters.

Computers and Technology
1 answer:
Serjik [45]1 year ago
4 0

Answer:

I am writing a JAVA and Python program. Let me know if you want the program in some other programming language.

import java.util.Scanner; // class for taking input from user

public class Reverse{ //class to reverse a sentence

public static void main(String[] args) { //start of main() function body

Scanner input = new Scanner(System.in); //create a Scanner class object

   System.out.print("Enter a sentence: "); //prompts user to enter a sentence

   String sentence = input.nextLine(); // scans and reads input sentence

   String[] tokens = sentence.split(" "); // split the sentence into tokens using split() method and a space as delimiter

   for (int i = tokens.length - 1; i >= 0; i--) { //loop that iterates through the tokens of the sentence in reverse order

       System.out.println(tokens[i]); } } } // print the sentence tokens in reverse order

Explanation:

In JAVA program the user is asked to input a sentence. The sentence is then broken into tokens using split() method. split method returns an array of strings after splitting or breaking the sentence based on the delimiter. Here the delimiter used is space characters. So split() method splits the sentence into tokens based on the space as delimiter to separate the words in the sentence. Next the for loop is used to iterate through the tokens as following:

Suppose the input sentence is "How are you"

After split() method it becomes:

How

are

you

Next the loop has a variable i which initialized to the tokens.length-1. This loop will continue to execute till the value of i remains greater than or equals to 0.

for (int i = tokens.length - 1; i >= 0; i--)

The length of first token i.e you is 3 so the loop executes and prints the word you.

Then at next iteration the value of i is decremented by 1 and now it points at the token are and prints the word are

Next iteration the value of i is again decremented by i and it prints the word How.

This can be achieved in Python as:

def reverse(sentence):

   rev_tokens = ' '.join(reversed(sentence.split(' ')))

   return rev_tokens

   

line = input("enter a sentence: ")

print((reverse(line)))

The method reverse takes a sentence as parameter. Then rev_tokens = ' '.join(reversed(sentence.split(' ')))  statement first splits the sentence into array of words/tokens using space as a delimiter. Next reversed() method returns the reversed sentence.  Next the join() method join the reversed words of the sentence using a space separator ' '.join(). If you want to represent the reversed tokens each in a separate line then change the above statement as follows:

rev_tokens = '\n'.join(reversed(sentence.split(' ')))  

Here the join method joins the reversed words separating them with a new line.

Simply input a line of text and call this reverse() method by passing the input line to it.

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Murrr4er [49]

Answer:

1

Explanation:

Anything to the 0th power is 1. However, 0⁰ is undefined.

5 0
2 years ago
Read 2 more answers
You are consulting for a trucking company that does a large amount ofbusiness shipping packages between New York and Boston. The
likoan [24]

Answer:

Answer explained with detail below

Explanation:

Consider the solution given by the greedy algorithm as a sequence of packages, here represented by indexes: 1, 2, 3, ... n. Each package i has a weight, w_i, and an assigned truck t_i. { t_i } is a non-decreasing sequence (as the k'th truck is sent out before anything is placed on the k+1'th truck). If t_n = m, that means our solution takes m trucks to send out the n packages.

If the greedy solution is non-optimal, then there exists another solution { t'_i }, with the same constraints, s.t. t'_n = m' < t_n = m.

Consider the optimal solution that matches the greedy solution as long as possible, so \for all i < k, t_i = t'_i, and t_k != t'_k.

t_k != t'_k => Either

1) t_k = 1 + t'_k

    i.e. the greedy solution switched trucks before the optimal solution.

    But the greedy solution only switches trucks when the current truck is full. Since t_i = t'_i i < k, the contents of the current truck after adding the k - 1'th package are identical for the greedy and the optimal solutions.

    So, if the greedy solution switched trucks, that means that the truck couldn't fit the k'th package, so the optimal solution must switch trucks as well.

    So this situation cannot arise.

  2) t'_k = 1 + t_k

     i.e. the optimal solution switches trucks before the greedy solution.

     Construct the sequence { t"_i } s.t.

       t"_i = t_i, i <= k

       t"_k = t'_i, i > k

     This is the same as the optimal solution, except package k has been moved from truck t'_k to truck (t'_k - 1). Truck t'_k cannot be overpacked, since it has one less packages than it did in the optimal solution, and truck (t'_k - 1)

     cannot be overpacked, since it has no more packages than it did in the greedy solution.

     So { t"_i } must be a valid solution. If k = n, then we may have decreased the number of trucks required, which is a contradiction of the optimality of { t'_i }. Otherwise, we did not increase the number of trucks, so we created an optimal solution that matches { t_i } longer than { t'_i } does, which is a contradiction of the definition of { t'_i }.

   So the greedy solution must be optimal.

6 0
2 years ago
Assign max_sum with the greater of num_a and num_b, PLUS the greater of num_y and num_z. Use just one statement. Hint: Call find
Gnoma [55]

Answer:

def find_max(num_1, num_2):

   max_val = 0.0

   if (num_1 > num_2): # if num1 is greater than num2,

       max_val = num_1 # then num1 is the maxVal.

   else: # Otherwise,

       max_val = num_2 # num2 is the maxVal

   return max_val

max_sum = 0.0

num_a = float(input())

num_b = float(input())

num_y = float(input())

num_z = float(input())

max_sum = find_max(num_a, num_b) + find_max(num_y, num_z)

print('max_sum is:', max_sum)

Explanation:

I added the missing part. Also, you forgot the put parentheses. I highlighted all.

To find the max_sum, you need to call the find_max twice and sum the result of these. In the first call, use the parameters num_a and num_b (This will give you greater among them). In the second call, use the parameters num_y and num_z (This will again give you greater among them)

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2 years ago
E-mail is an efficient means of disseminating information quickly and inexpensively. However, HIPAA regulations affect e-mail us
oksano4ka [1.4K]

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Explanation:

No doubt Email is an inexpensive efficient means of communicating quickly. But it is prone to hacking and it is not a secure mechanism. In order to add security ,the Email needs to be sent in an encrypted form. Banking and HIPAA regulations require the emails to be sent in encrypted form as it is a secure mechanism. Even if one has the consent from the client , the Email has to be in encrypted. Even if the Organization's e-mail system has appropriate firewalls and related infrastructure , the golden rule is to send encrypted format Emails.

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NikAS [45]

Answer:

C++.

Explanation:

<em>Code snippet.</em>

#include <map>

#include <iterator>

cin<<N;

cout<<endl;

/////////////////////////////////////////////////

map<string, string> contacts;

string name, number;

for (int i = 0; i < N; i++) {

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   cin<<number;

   cout<<endl;

   contacts.insert(pair<string, string> (name, number));

}

/////////////////////////////////////////////////////////////////////

map<string, string>::iterator it = contacts.begin();

while (it != contacts.end())  {

   name= it->first;

   number = it->second;

   cout<<word<<" : "<< count<<endl;

   it++;

}

/////////////////////////////////////////////////////////////////////////////////////////////////////////

I have used a C++ data structure or collection called Maps for the solution to the question.

Maps is part of STL in C++. It stores key value pairs as an element. And is perfect for the task at hand.

8 0
2 years ago
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