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forsale [732]
2 years ago
12

A man has a 10m X 10m square garden. In the center is a 2m X 2m square patch which he cannot use. He divides his usable space in

to four congruent rectangular patches, each of which measures
Mathematics
1 answer:
ra1l [238]2 years ago
8 0

Answer:

4m X 6m

Step-by-step explanation:

This is because if there is a 2m square in the middle, there is 8 m of usable space left along both sides of the garden.

Because the 2m square was in the middle, there is 8/2 = 4m along each width of the 4 small rectangles.

Becuase 4m is the width, there is 10 - 4 = 6m along each rectangle's length.

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When you are out in the sunshine you feel warm because the _____ energy excites the molecules of your skin and creates heat ther
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You feel warm because the suns energy excites your molecules

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2 years ago
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When equation represents the function f(x)=(1.6)x after it has been translated 5 units up 9 units to the right?
wel
For this question my answer would be

g(x)=(1.6)x-9+5

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5 0
2 years ago
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Huang buys 3 shirts that each cost the same amount, a pair of pants that cost $12, and he pays with a $100 bill. Which
nekit [7.7K]

Answer:

(100 – 12) – 3x

Step-by-step explanation:

(100 – 12) – 3x would be the correct answer because:

100 is the total amount he paid

12 is the cost of pants

because we don't know the price of shirts yet so it would be called x

He buy in total of 3 shirts so the equation for the price would be 3 * x = 3x

So it would be:

total money paid - pants costs - shirts cost

= 100 - 12 - 3x or (100 - 12) -3x

Hope this helped :3

8 0
2 years ago
Read 2 more answers
A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro
Rom4ik [11]

Answer:

765 J

Step-by-step explanation:

We are given;

Mass of bucket = 30 kg

Mass of rope = 0.3 kg/m

height of building= 30 meter

Now,

work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand

Or W = W1 + W2

Work done in lifting the rope is given as,

W1 = Force x displacement

W1 = (30,0)∫(0.2x .dx)

Integrating, we have;

W1 = [0.2x²/2] at boundary of 30 and 0

W1 = 0.1(30²)

W1 = 90 J

work done in lifting the sand is given as;

W2 = (30,0)∫(F .dx)

F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

W2 = (0.5 × 30²)/2) + 15(30)

W2 = 225 + 450

W2 = 675 J

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,

W = 90 + 675

W = 765 J

5 0
2 years ago
For what values of m does the graph of y = 3x^2 + 7x + m have two x-intercepts? a) m>12/49 b) m<12/49 c) m<49/12 d) m&g
den301095 [7]

The quadratic formula, has a part we call the "discriminant" defined by the variables that are inside the square root, and is denotated by "delta":

<span>Δ=<span>b2</span>−4ac</span> Whenever we solve a quadratic equation that is complete and we analyze the discriminant, we can get 3 scenarios: <span>if→Δ>0<span>=></span>∃<span>x1</span>,<span>x2</span>/a<span>x2</span>+bx+c=0</span> This just means: "if the discriminant is greater than zero, there will exist two x-intercepts" And for the second scenario: <span>if→Δ=0→∃<span>xo</span>/a<span>x2</span>+bx+c=0</span> This means: "if the discriminant is equal to zero, there will be one and only one x-intercept" And for the last scenario: <span>if→Δ<0→∃x∉R/a<span>x2</span>+bx+c=0</span> This means that :"if the discriminant is less than zero, there will be no x-intercepts" So, if we take your excercise and analyze the the discriminant: <span>3<span>x2</span>+7x+m=y</span> we will find the values that satisfy y=0 : <span>3<span>x2</span>+7x+m=0</span> And we'll analyze the discriminant: <span>Δ=<span>72</span>−4(3)(m)</span> And we are only interested in the values that make the discriminant equal zero: <span><span>72</span>−4(3)(m)=0</span> All you have to do is solve for "m".

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