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Delicious77 [7]
2 years ago
13

G(x)= -\dfrac{x^2}{4} + 7g(x)=− 4 x 2 ​ +7g, left parenthesis, x, right parenthesis, equals, minus, start fraction, x, squared,

divided by, 4, end fraction, plus, 7 What is the average rate of change of ggg over the interval [-2,4][−2,4]open bracket, minus, 2, comma, 4, close bracket?
Mathematics
1 answer:
RUDIKE [14]2 years ago
6 0

Answer:

<h2>-1/2</h2>

Step-by-step explanation:

Given the function G(x)= -\dfrac{x^2}{4} + 7, the average rate of change of g(x) over the interval [-2,4], is expressed as shown below;

Rate of change of the function is expressed as g(b)-g(a)/b-a

where a - -2 and b = 4

G(4)= -\dfrac{4^2}{4} + 7\\G(4)= -\dfrac{16}{4} + 7\\G(4)= -4 + 7\\G(4) = 3\\

G(-2) = -\dfrac{(-2)^2}{4} + 7\\G(-2)= -\dfrac{4}{4} + 7\\G(-2)= -1 + 7\\G(-2)= 6

average rate of change of g(x) over the interval [-2,4] will be;

g'(x) = \frac{g(4)-g(-2)}{4-(-2)}\\ g'(x) = \frac{3-6}{6}\\\\g'(x) = -3/6\\g'(x) = -1/2

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In a particular city, 82% of the residents have a desktop computer, 47% have a desktop computer and a laptop computer, and 3% ha
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Answer:

B) 0.57

Step-by-step explanation:

Let's define:

  • A: the home has a laptop
  • B: the home has a desktop computer.

Data

  • P(B) = 0.82
  • P(A∩B) = 0.47

We want to find the probability that a home has a laptop given that it has a  desktop computer, that is, P(A|B).

P(A|B) = P(A∩B)/P(B) = 0.47/0.82 = 0.57

3 0
2 years ago
a hockey team ordered 12 wooden pedestals to mount their brass trophies on. The design pedestal is shown below. The teal is char
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8 0
2 years ago
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A bunch bowl is in the shape of a hemisphere. The top rim has a circumference of 116cm.
Tom [10]
The hemisphere is half the volume of a sphere. Since we are given the circumference, we can solve for the radius of the sphere. That is 
     C=2\pi r

     116\:cm=2\pi r

     r=\frac{116}{2\pi }=18.462\:cm

Part A
We can now compute for the volume of the hemisphere.
     V=\frac{1}{2}\times \frac{4}{3}\pi r^3=\frac{1}{2}\times \frac{4}{3}\pi \left(18.462\right)^3=13179\:cm^3

Part B
We just need to convert the volume into its corresponding gallons
     13179\:cm^3\times \frac{1\:Liter}{1000\:cm^3}\times \frac{1\:gallon}{3.785\:Liters}=3.5\:gallons
8 0
2 years ago
Describe any domain restrictions that make sense for each of these scenarios: The price of a stock fluctuates several times thro
mrs_skeptik [129]

Answer:

  • a) Restriction: days of the year (a discrete time)

  • b) The time the ball is on the air: t = 0, until the balls touchs the ground (any real value from t = 0 to t when the ball hits the ground)

  • c) Any positive real value: x ≥ 0

Explanation:

The <em>domain </em>is the set of elements that can be inputs of the <em>function</em>.

<u><em>1. The price of a stock fluctuates several times throughout the year as a function of time.</em></u>

The input variable is the time through out the year.

If you assume that the fluctuaion is recorded once a day, and not every second, the logical assumption is that the time is a day of the year.

Thus, the restricion is the days of the year.

You could represent them in different forms, like DD/MM/YY, or even as a number from 1 to 365 if it covers just one year.

<u><em></em></u>

<u><em>2. A ball is hit into the air by a baseball player, rises until it reaches its highest point, and then falls into left field.</em></u>

The domain is the time the ball is on the air, which may be any real value from t = 0, until the balls touchs the ground.

It is not restricted to integer numbers.

<u><em>3. The volume of a spherical balloon increases as the balloon is blown up and decreases as air is let out of it.</em></u>

The inputs of the function are amounts of air, which may be measured as number of moles.

The number of moles can be any real value equal or greater than zero.

Thus, the domain is the positive real values x ≥ 0.

8 0
2 years ago
Read 2 more answers
Triangles A B C and R M Q are shown. Angles C A B and M R Q are 29 degrees. Angles A B C and R M Q are 116 degrees. What additio
Svetlanka [38]

Answer:

Therefore, the two options for triangles to be congruent using AAS are

1. BC ≅ MQ       (Additional information)

2. AC ≅ RQ       (Additional information)

Step-by-step explanation:

Given:

∠CAB =∠MRQ = 29°

∠ABC = ∠RMQ = 116°

To Prove:

Δ ABC ≅ ΔRMQ  by AAS congruence test which additional information is required

Proof:

<u>Case 1.</u>

In  Δ ABC and Δ RMQ

∠CAB =∠MRQ = 29°      ……….{Given}

∠ABC = ∠RMQ = 116°     ..……..{Given}

BC ≅ MQ                        ……….{Additional information required}

Δ ABC ≅ Δ RMQ ….{By Angle-Angle-Side congruence test}

<u>Case 2.</u>

In  Δ ABC and Δ RMQ

∠CAB =∠MRQ = 29°      ……….{Given}

∠ABC = ∠RMQ = 116°     ..……..{Given}

AC ≅ RQ                        ……….{Additional information required}

Δ ABC ≅ Δ RMQ ….{By Angle-Angle-Side congruence test}

Therefore, the two options for triangles to be congruent using AAS are

1. BC ≅ MQ       (Additional information)

2. AC ≅ RQ       (Additional information)

3 0
2 years ago
Read 2 more answers
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