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1 year ago

4 (hx - 1) -3 (x +h) ≡ 5 (x + k) Work out the value of h and k H and k are integer constants

Mathematics

1 answer:

vladimir1956 [14]1 year ago

6 0

Answer:

4hx - 8x - 3h - 4

k = ------------------------

8x + 5k + 4

h = ------------------------

4x - 3

Step-by-step explanation:

4 (hx - 1) - 3 (x + h) = 5 (x + k)

4hx - 4 - 3 (x + h) = 5 (x + k)

4hx - 4 - 3x - 3h = 5 (x + k)

4hx - 4 - 3x - 3h = 5x + 5k add 3h both sides

4hx - 4 - 3x - 3h + 3h = 5x + 5k + 3h simplify

4hx - 4 - 3x = 5x + 5k + 3h add 4 both sides

4hx - 4 - 3x + 4 = 5x + 5k + 3h + 4 simplify

4hx - 3x = 5x + 5k + 3h + 4 subtract 5x from both sides

4hx - 3x - 5x = 5x + 5k + 3h + 4 - 5x simplify

4hx - 8x = 5k + 3h + 4

4hx - 8x - 3h - 4 = 5k

4hx - 8x - 3h - 4

k = ------------------------

<u>solving for h;</u>

4hx - 3h = 8x + 5k + 4

h(4x - 3) = 8x + 5k + 4

8x + 5k + 4

h = ------------------------

4x - 3

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On any given day, Juan will break even if he earns as much money as he spends. On day 5, he records the expression 16+ (-16). Do

sertanlavr [38]

Answer:

Yes. Juan will break even because 16 and -16 are a zero pair. -16 is the additive inverse of 16. So the sum will be 0.

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2 years ago

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The linearized regression equation for an exponential data set is log ŷ = 0.14x + 0.4, where x is the number of years and y is t

djyliett [7]

Option C: $316$ is the predicted population when $x=15$

Explanation:

The regression equation for an exponential data is $\log y=0.14x+0.4$

Where x is the number of years and

y is the population

We need to determine the predicted population when $x=15$

The population x can be determined by substituting $x=15$ in the equation $\log y=0.14x+0.4$

Thus, we have,

$\log y=0.14(15)+0.4$

$\log y=2.1+0.4$

$\log y=2.5$

Using the logarithmic definition $\log _{a}(b)=c$ then $b=a^{c}$

$\log _{10}(y)=2.5 \Rightarrow y=10^{2.5}$

$y=316.22776 \ldots$

Rounding off to the nearest whole number, we get,

$y=316$

Thus, the predicted population when $x=15$ is 316

Hence, Option C is the correct answer.

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2 years ago

A point in the figure is selected at random. Find the probability that the point will be in the part that is NOT shaded.

Dovator [93]

Answer:

Step-by-step explanation:

So the question really is what is the probability that the point is in the square? You cannot pick something surrounding the circles because you do not know anything about that region.

This is solved by comparing areas. There are 2 full circles there. 1 circle has an area of pi*r^2

Total shaded area = 2 * pi * r^2.

Let r = 3 This is a completely random choice. No matter what number you choose for r, the answer will come out the same. When you get along a little further in math, you will find that you can just use letters.

Total shaded area = 2 * 3.14 * 3^2

Total shaded area = 2 * 3.14 * 9

Total shaded area = 56.55

Total area of the square.

s = 2*r

s = 2*3

s = 6

Area of the square = 6^2 = 36

Total area of both regions = 56.55 + 36 = 92.55

Answer

% = (area of square) * 100% / Total area of both regions

% = 3600 / 92

% = 39%

Obviously the answer I get is not offered. The closest answer is B so I will choose that.

==========================

This is how this question would be done without using any value for r.

Area of shaded region = 2 pi r^2 = 6.28 r^2

Area of square = d^2 where d = 2r

Area of square = 4 r^2

Total area = 6.28 r^2 + 4r^2 = 10.28 r^2

Area of square to total = (4r^2/10.28 r^2 ) * 100%

Area of square to total (as a %) = 4/10.28 * 100 = 39% which gives the same answer.

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2 years ago

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−7x−50≤−1 AND−6x+70>−2

fgiga [73]

Answer:

$-7\geq x$ and $[-7,12)$ in interval notation.

Step-by-step explanation:

We have been given a compound inequality $-7x-50\leq -1\text{ and }-6x+70>-2$ . We are supposed to find the solution of our given inequality.

First of all, we will solve both inequalities separately, then we will combine both solution merging overlapping intervals.

$-7x-50\leq -1$

$-7x-50+50\leq -1+50$

$-7x\leq 49$

Dividing by negative number, flip the inequality sign:

$\frac{-7x}{-7}\geq \frac{49}{-7}$

$x\geq -7$

$-6x+70>-2$

$-6x+70-70>-2-70$

$-6x>-72$

Dividing by negative number, flip the inequality sign:

$\frac{-6x}{-6}$

$x$

Upon merging both intervals, we will get:

$-7\geq x$

Therefore, the solution for our given inequality would be $-7\geq x$ and $[-7,12)$ in interval notation.

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2 years ago

Three highways connect city A with city B. Two highways connect city B with city C.

QveST [7]

(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:
$0.992\times0.96=0.9523$

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become: $0.9984\times0.96=0.95846$

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:
$0.992\times0.992=0.9841$

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
$P(A\cup B)=P(A)+P(B)-P(A\cap B)$
$0.9523+0.8-(0.9523\times0.8)=0.99$
Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.

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2 years ago