Answer:
a = 0.25
Step-by-step explanation:
Our strategy to solve this problem will be to use the information given in the table to obtain first the value of c in the quadratic equation which has the form ax^2 + bx + c and then form a system of 2 linear equations and solve for the coefficients a and b as follow:
from x=0 and y=-3 a*0 + b* 0 + c = - 3
c = -3
from x=1 and y= -3.75
a*(1) + *(1) + (-3) = -3.75
a + b = -3.75 + 3 = -0.75
from x= 2 and y = -4
a* (2)^2 + b*(2) + (-3) = -4
4a + 2b = -4 +1
4a + 2b = -1
Now we can solve the system f equations by elimination:
a + b = -0.75
4a + 2b = -1
multiply first equation by -2 and add to the second and get
-2a - 2b = +1.50
4a + 2b = -1
2a = 0.50 and substituting into any of the equations get b = -1
so the quadratic equation has a= 0.25 b= -1 c= -3
we can even plug the any of the other values for x given in the table and check the answer.
S(p) = 400 - 4p + 0.00002p^4
D(p) = 2800 - 0.0012p^3
S(p) = D(p)
400 - 4p + 0.00002p^4 = 2800 - 0.0012p^3
0.00002p^4 + 0.0012p^3 - 4p - 2400 = 0
p = $96.24
X - the number of sandwiches ordered
y - the number of soups ordered
There were 18 people, and each person ordered either one soup or one sandwich.

The sandwiches cost $7.75 each, the soups cost $4.50 each. The total cost was $113.50.

Set up a system of equations:

10 sandwiches were ordered.
The answer is D.
Answer:
251 inches
Step-by-step explanation:
c = 2πr
c = 2(3.14)(5) = 31.4
31.4 x 8 rev. = 251 inches
Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) = 
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50