When the movie is half over, popcorn sells for half price. Which expression can be used to determine the new cost for 3 orders o
2 answers:
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Answer:
(A) 0.15625
(B) 0.1875
(C) Can't be computed
Step-by-step explanation:
We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.
Let X = Amount of time taken by student to complete a statistics quiz
So, X ~ U(32 , 64)
The PDF of uniform distribution is given by;
f(X) = , a < X < b where a = 32 and b = 64
The CDF of Uniform distribution is P(X <= x) =
(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)
P(X > 59) = 1 - P(X <= 59) = 1 - = 1 -
=
= 0.15625
(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)
P(X <= 43) = =
= 0.34375
P(X < 37) = =
= 0.15625
P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875
(C) Probability that student complete the quiz in exactly 44.74 minutes
= P(X = 44.74)
The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.
ANSWER
The set of all rational numbers and the set of all real numbers.
EXPLANATION
The set of rational numbers contains all numbers that can be written in the form,
where a and b are integers and b≠0.
The given number is
It belongs to the set of rational numbers.
The set of rational numbers is a subset of the set of real numbers.
Hence
also belongs to the set of real numbers.
The correct answer is A.
The set of all rational numbers and the set of all real numbers.
EXPLANATION
The set of rational numbers contains all numbers that can be written in the form,
where a and b are integers and b≠0.
The given number is
It belongs to the set of rational numbers.
The set of rational numbers is a subset of the set of real numbers.
Hence
also belongs to the set of real numbers.
The correct answer is A.
Answer:
y2 = (6x + 7)/36 + (Dx + E)e^x
Step-by-step explanation:
The method of reduction of order is applicable for second-order differential equations.
For a known solution y1 of a 2nd order differential equation, this method assumes a second solution in the form Uy1 which satisfies the said differential equation. It then assumes a reduced order for U'' (w' = U'').
The differential equation becomes easy to solve, and all that is left are integration and substitutions.
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