Answer:
The correct option is;
B. The photo is a digital representation of the analog painting
Explanation:
The forming of a encoded digital representation of the an object's physically as visually or observed characteristics is known as digital imaging such that there is an implied application of digital processing to the (otherwise analogue) image such as printing, display, storage, or compression of the original image.
With a digital image, copies can be made of the captured image an infinite amount of time while still maintaining the quality of the original copied image.
A painting made by the use of pencils, paints, canvases, and films is known as an analog art or painting.
Answer:
O.15
Explanation: The missing probability, P(X = 0) = 1 – 0.26 – 0.29 – 0.15 – 0.05 = 0.25.
ux= (0)(0.25) + (1)(0.26) + (2)(0.29) + (3)(0.15) + (4)(0.05) = 1.49 children.
P(X < 1.49) = P(X = 0 or X = 1) = 0.25 + 0.26 = 0.51.
<u>Answer:</u>
A workplace is a place where somebody is employed by his or her employer. There are four main types of corporate cultures:
- An organization of stars (competitively);
- An organization based on the cause; and
- A company that believes in doing wonderful things while it's still small.
My Ideal workplace:
"I love a quick pace atmosphere which allows to develop my talents by learning from other members of the team more of like an organization of stars, in which I can have both competition and smooth working relationship with the people around me. While I'm doing my best in a calm atmosphere myself, I really like grabbing coffee in my leisure time with teammates(informal) and working together using ideas(formal)”.
Answer:
The standard deviation is 4.83 inches.
Explanation:
We are given that the average yearly snowfall in Chillyville is Normally distributed with a mean of 55 inches.
The snowfall in Chillyville exceeds 60 inches in 15% of the years, we have to find the standard deviation.
Let X = <u><em>the average yearly snowfall in Chillyville</em></u>.
The z-score probability distribution for the normal distribution is given by;
Z = 
~ N(0,1)
where, 
= mean amount of rainfall = 55 inches
= standard deviation
Now, it is stated that the snowfall in Chillyville exceeds 60 inches in 15% of the years, that means;
P(X > 60 inches) = 0.15
P( > 
) = 0.15
P(Z > ) = 0.15
In the z table, the critical value of z that represents the top 15% of the area is given as 1.0364, that means;
= 4.83 inches
Hence, the standard deviation is 4.83 inches.
Answer:
His average for 4 days is 2542.5 mg
Intake of 5th day has to be less than 1330 mg
Explanation:
In order to find the average we take the sum of intakes for 4 day ans then divide it by total number of day which is 4 days.
Average = (2150 + 3005 + 2700 + 2315) / 4
Average = 10170/4
Average = 2542.5 mg
To find the 5th day intake such that average is below 2300 mg:
Let 5th day intake = x
We apply the same method to find the average by taking the sum of intakes for 5 days and then dividing the total with 5 days now. This average has to be less than 2300 mg therefore we use the following method:
(2150 + 3005 + 2700 + 2315 + x ) / 5 < 2300
2300 = (10170 + x)/ 5 < 2300
10170 + x < 11500
x < 11500 - 10170
x < 1330 mg
