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zhuklara [117]
2 years ago
10

One day, Mark notices that Karen is cleaning up Daniel's room for the 4th time this week. When he approaches her about it later,

she dismisses him - saying that Daniel has just been really busy with his extra-curricular activities. However at dinner that night, Daniel decides he doesn't want to play on the tennis team anymore. Karen reminds him that her and Mark both played tennis growing up; further, Karen reminds him that she has been helping him out a lot so he can play tennis - by cleaning his room, buying him items he needs, etc. Daniel slumps his shoulders after a moment and says "you're right." Mark thinks Karen is trying to play the _ (blank) _ type of parent.
Biology
1 answer:
Radda [10]2 years ago
7 0

Answer:

Mark thinks Karen is trying to represent the democratic type of parent.

Explanation:

Karen did not impose that Daniel keep playing tennis, which indicates that she is not trying the authoritarian style of parenting. Furthermore, she is not failing to care whether or not Daniel will stop playing tennis, which indicates that she is not trying the negligent parenting style.

However, Karen preferred to explain to Daniel that playing tennis is a beneficial activity and that she is helping him to stay on the team, which made Daniel reason and realize that she was right. This is an example of the democratic type of parentability, where countries explain their opinions on a particular topic, but allow their children to make their own decisions, without imposing reprisals, and without acting as if they don't care.

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Two autosomal genes, J and K, are 60 map units apart. You perform the following testcross: J K / j k x j k / j k. At what freque
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  • j k / j k = 20%
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  • j K / j k = 30%                

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To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.

So, en the exposed example:

  • J and K are autosomal genes
  • J and K are separated by 60 M.U.
  • 60 M.U. means that there is 60% of recombination.

Cross)             J K / j k                    x                  j k / j k

Gametes) JK  Parental                                     jk, jk, jk, jk

                jk   Parental                                  

                Jk   Recombinant                          

                 jK   Recombinant

One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.

1 M.U. -------------- 1% recombination

60 M.U. ------------ 60% recombination

                              30% Jk  +  30% jK

100 M.U. - 60 M.U. = 40 M.U.

40M.U.--------------40 % Parental (Not recombinant)

                            20% JK   +   20% jk

Punnet Square)           JK       jk      Jk      jK

                          jk     JK/jk   jk/jk   Jk/jk   jK/jk

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%                                

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