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Helen [10]
2 years ago
6

Select the correct answer.

Computers and Technology
1 answer:
gizmo_the_mogwai [7]2 years ago
5 0

Answer:

D

Explanation:

Hard work and dedication prove that you will be there and do what you need to.

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____ twisted pair is the least quality twisted pair wire that should be used in a data/voice application.
xxMikexx [17]

Answer:

Category 5 (Cat 5) twisted pair is the least quality twisted pair wire that should be used.

Explanation:

The reason is as follows:

  1. Category 1 twisted pair is not suitable for transmitting data but comes in handy for telephone communications. Hence, it should not be used in a data/voice application.
  2. Category 2 twisted pair is suitable for data transmission, however, it can only transmit at 4Mbps which is very slow. Hence, it should not be used in a data/voice application.
  3. Category 3 twisted pair can transmit data with speed reaching 10Mbps which is slow for voice/data communication.
  4. Category 4 twisted pair can transmit data with speed reaching 16Mbps and is used in token ring networks. It is slow for communicating in a voice/data application.
  5. Category 5 twisted pair is the least qualified to be used in a voice/data application because it can transmit data at speeds that reach 100Mbps.

Hence, Cat 5 or Category 5 twisted pair is the least quality twisted pair that should be used in a data/voice application.

6 0
2 years ago
Modify the TimeSpan class from Chapter 8 to include a compareTo method that compares time spans by their length. A time span tha
My name is Ann [436]

Answer:

Check the explanation

Explanation:

Here is the modified code for

TimeSpan.java and TimeSpanClient.java.

// TimeSpan.java

//implemented Comparable interface, which has the compareTo method

//and can be used to sort a list or array of TimeSpan objects without

//using a Comparator

public class TimeSpan implements Comparable<TimeSpan> {

   private int totalMinutes;

   // Constructs a time span with the given interval.

   // pre: hours >= 0 && minutes >= 0

   public TimeSpan(int hours, int minutes) {

        totalMinutes = 0;

        add(hours, minutes);

   }

   // Adds the given interval to this time span.

   // pre: hours >= 0 && minutes >= 0

   public void add(int hours, int minutes) {

        totalMinutes += 60 * hours + minutes;

   }

   // Returns a String for this time span such as "6h15m".

   public String toString() {

        return (totalMinutes / 60) + "h" + (totalMinutes % 60) + "m";

   }

   // method to compare this time span with other

   // returns a negative value if this time span is shorter than other

   // returns 0 if both have same duration

   // returns a positive value if this time span is longer than other

   public int compareTo(TimeSpan other) {

        if (this.totalMinutes < other.totalMinutes) {

            return -1; // this < other

        } else if (this.totalMinutes > other.totalMinutes) {

            return 1; // this > other

        } else {

            return 0; // this = other

        }

   }

}

// TimeSpanClient.java

public class TimeSpanClient {

   public static void main(String[] args) {

        int h1 = 13, m1 = 30;

        TimeSpan t1 = new TimeSpan(h1, m1);

        System.out.println("New object t1: " + t1);

        h1 = 3;

        m1 = 40;

        System.out.println("Adding " + h1 + " hours, " + m1 + " minutes to t1");

        t1.add(h1, m1);

        System.out.println("New t1 state: " + t1);

        // creating another TimeSpan object, testing compareTo method using the

        // two objects

        TimeSpan t2 = new TimeSpan(10, 20);

        System.out.println("New object t2: " + t2);

        System.out.println("t1.compareTo(t2): " + t1.compareTo(t2));

        System.out.println("t2.compareTo(t1): " + t2.compareTo(t1));

        System.out.println("t1.compareTo(t1): " + t1.compareTo(t1));

   }

}

/*OUTPUT*/

New object t1: 13h30m

Adding 3 hours, 40 minutes to t1

New t1 state: 17h10m

New object t2: 10h20m

t1.compareTo(t2): 1

t2.compareTo(t1): -1

t1.compareTo(t1): 0

4 0
2 years ago
The hostel in which you plan to spend the night tonight offers very interesting rates, as long as you do not arrive too late. Ho
faust18 [17]

Answer:

Answered below

Explanation:

// Python implementation

incrementAmount = 5

basePrice = 10

price = 0

arrivalHour = int(input("Enter arrival hour 0-12: ")

if arrivalHour < 0 or arrivalHour > 12:

print ("Invalid hour")

if arrivalHour == 0:

price = basePrice

else:

price = arrivalHour * incrementAmount

totalPrice = price + basePrice

if totalPrice > 53:

totalPrice = 53

print ("Your bill is $totalPrice")

4 0
2 years ago
A(n) ______of the audio or video clip makes the content easily accessible to people with hearing disabilities.
defon

subtitles

hope that helped you

7 0
2 years ago
Read 2 more answers
Anna bought a box of blueberries for £7. She used 700 grams for a cheesecake and she has 450 grams left. How much did the bluebe
xxTIMURxx [149]

0.61 (rounded up)

Explanation:

You add both 700 and 450 which will give you 1150g

You then divide 1150 by 100 which gives you 11.5

Then divide 7 by 11.5 which will give you 0.61 as cost of every 100 grams

8 0
2 years ago
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