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rusak2 [61]
2 years ago
6

How did Roderick Murchison's and Charles Lapworth's views of the formation of Scotland's mountains differ?​

Geography
1 answer:
Nostrana [21]2 years ago
3 0
Roderick described everything in the region as a silurian in age because the rocks were either metamorphic or barren sedimentary layers and he had little fossil data to countermand or support. While with Charles he suggested that movement along low angle reverse faults , which the fault plane is parallel to the bedding plane , where it had brought schists from east to west , overriding younger sedimentary strata.
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These problems can be tackled by adopting alternate techniques and correctify the impact of cattle ranching and soy farming. 

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Why do slums exist? - APEX
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The metal alloy that makes up the core of Earth is ________, as compared to the rocky mantle. A. less dense B. denser C. very si
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5 0
2 years ago
The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm. What is the approx
ipn [44]

Answer:  44.8\°

Explanation:

We have a right triangle with sides AB, BC=5cm and AC=13cm (the hypotenuse). Let's apply the Pithagorean Theorem to find AB:

AC^{2}=AB^{2} + BC^{2}  (1)

AB^{2}=AC^{2} - BC^{2} (2)

AB^{2}=(13cm)^{2} - (5cm)^{2} (3)

AB=12cm (4)

Now that we know the value of each side of the triangle, we will use the trigonometric function sine to find the angles C and A (angle B is 90\° remembering we are talking about a right triangle):

For angle C:

sinC=\frac{Oppositeside}{Hypotenuse}

sinC=\frac{12}{13}  (5)

C=sin^{-1}(\frac{12}{13})  (6)

C=67.38\°  (7)

For angle A:

sinA=\frac{5}{13}  (8)

A=sin^{-1}(\frac{5}{13})  (9)

A=22.62\°  (10)

Calculating the difference between both angles:

C-A=67.38\°- 22.62\°

C-A=44.76\° \approx 44.8\°

6 0
2 years ago
Read 2 more answers
5. How fast did the shoes travel? (4 points) a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49
Leto [7]

Answer:

a) d = 35.0143 Km

t = 188 days

v = 7.76*10⁻³ Km/h

b) d = 28.6356 Km

t = 2165 days

v = 5.51*10-4 Km/h

Explanation:

a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49°N, 126°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((49-48)²+(126-161)²) = 35.0143 Km

How many days did they take to travel that distance? (You can use November 30 as the date found).  

From May 27, 1990 to November 30, 1990 we have

t = 5 days + (30 days/month)*(3 months) + (31 days/month)*(3 months) = 188 days

⇒   t = 188 days = (188 days)*(24 hours/day) = 4512 hours

What was their rate of travel in kilometers per hour?  

We use the equation

v = d/t   ⇒   v =  35.0143 Km/ 4512 h

⇒   v = 7.76*10⁻³ Km/h

b. From where the shoes spilled (48°N, 161°W) to where they were found in 1996 (54°N, 133°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((54-48)²+(133-161)²) = 28.6356 Km

How many days did they take to travel that distance (use April 30 as the date found)?  

From May 27, 1990 to April 30, 1996 we have

t = 5 days + (30 days/month)*(4 months) + (31 days/month)*(6 months) + 29 days + (365 days/ year)*(4 years)+ (366 days/ year)*(1 year)= 2165 days

⇒   t = 2165 days = (2165 days)*(24 hours/day) = 51960 hours

What was their rate of travel in kilometers per hour?

We use the equation

v = d/t   ⇒   v =  28.6356 Km/ 51960 h

⇒   v = 5.51*10-4 Km/h

7 0
2 years ago
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