<span>Fresh water freezes at 32 degrees Fahrenheit, and as salinity increases, the required temperature to freeze decreases.
The freezing point for water at 18 0/00 is 30.233 degrees Fahrenheit. So, for the black sea to freeze, it would need to be less than about thirty and a quarter degrees in both areas. Further for the Adriatic not to freeze it must be assumed that the Adriatic's salinity is higher, probably significantly higher as to avoid even partially freezing.
Furthermore, as the Black Sea's decreased salinity is attributed to nearby freshwater runoff, it is safe to assume that the Adriatic Sea either A) Has little or no freshwater runoff, or B) Has a mitigating factor that negates any freshwater runoff, allowing the salinity of its water to remain high.</span>
Answer:
Pacific Northwest is the region where the tribes live.
Was that while much of Egypt is desert, the fertile Nile River Valley provided the ancient Egyptians. With the means to sustain life. So, in addition to river systems and land quality, other natural resources. Such as iron ore, copper, and gold. Had affected where civilizations developed.
Mohamed and Li Jing were asked to find an explicit formula for the sequence -5\,,-25\,,-125\,,-625,...−5,−25,−125,−625,...Minus,
ANTONII [103]
Answer:
the equation is given as 
Explanation:
As the sequence is given as −5,−25,−125,−625,...
From this the first term is given as
a1=-5
Now the relation between this term and the next term is to be observed.
d=a2-a1=-25-(-5)=-25+5=-20
d=a3-a2=-125-(-25)=-125+25=-100
Now it is observed that the difference is not same this indicates that the relation is not arithmetic.
next up is the geometric sequence so the value of ratio is given as
r=a2/a1=-25/-5=5
r=a3/a2=-125/-25=5
As the ratio is same this indicates, this is a geometric sequence.
Now for the geometric sequence, the value of the general term is given as

Here a1=-5 and r=5 so the equation is given as

Because fossil fuels are limited, and will eventually run out entirely at the current rate we are using them.