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Lera25 [3.4K]
1 year ago
5

the length of the swimming pool is 8 m longer than its width and the area is 105 m squared write in quadratic equation ​

Mathematics
1 answer:
weqwewe [10]1 year ago
5 0

Answer:

Step-by-step explanation:

The length of the swimming pool is 8m longer than it's width.

If we say L = length, W = width

From the information above, we can say

L= 8 + w

We are also told the area is 105 m squared.

<em>Note: </em>

<em>Area of a Rectangle = Length x Width </em>

105 =  (8 + w ) x w

105 = 8w + w^2\\

Subtract 105 from both sides:

w^2 + 8w - 105 = 0

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Multiple 7/9 to the sum of 8 3/7 and 5 11/14
Brums [2.3K]

\frac{7}{9} \times (8 \frac{3}{7} + 5 \frac{11}{14}) =  \\

\frac{7}{9} \times (8 \frac{6}{14} + 5 \frac{11}{14}   ) =  \\

\frac{7}{9} \times (13 \frac{6 + 11}{14}) =  \\

\frac{7}{9}  \times (13 \frac{17}{14}) =  \\

\frac{7}{9} \times (14 \frac{3}{14}) =  \\

\frac{7}{9} \times ( \frac{14 \times 3 + 3}{14}) =  \\

\frac{7}{9} \times ( \frac{42 + 3}{14}) =  \\

\frac{7}{9} \times ( \frac{45}{14}) =  \frac{7 \times 45}{9 \times 14} =  \frac{5}{2}  \\

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

4 0
2 years ago
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Cheyenne and Jacob are geocaching. They are currently hiking on a main trail at a bearing of N 45° E. They determine that the ca
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Answer:

1.8 miles

Step-by-step explanation:

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2 years ago
Find the range of y=3/2cos4x-1
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Answer:

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

Step-by-step explanation:

Smallest value of cos α = - 1,

largest value of cos α = 1.

When cos 4x = - 1,  y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5

When cos 4x = 1,  y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

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The cost of a parking permit consists of a one-time administration fee plus a monthly fee. A permit purchased for 12 months cost
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The U.S. Bureau of Labor Statistics reports that 11.3% of U.S. workers belong to unions (BLS website, January 2014). Suppose a s
andrezito [222]

Answer:

a) Null hypothesis:p \leq 0.113  

Alternative hypothesis:p > 0.113  

b) z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074  

The p value for this case would be given by:

p_v =P(z>1.074)=0.141  

c) For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

Step-by-step explanation:

Information given

n=400 represent the random sample taken

X=52 represent the  workers belonged to unions

\hat p=\frac{52}{400}=0.13 estimated proportion of workers belonged to unions

p_o=0.113 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

Part a

We want to test if the true proportion of interest is higher than 0.113 so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.113  

Alternative hypothesis:p > 0.113  

Part b

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074  

The p value for this case would be given by:

p_v =P(z>1.074)=0.141  

Part c

For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

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