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2 years ago

Write a word problem that involves multiplication and addition. Include extra numerical information

2 answers:

8 0

Sally bought 5 apples at the store. Her friend, jenny, bought 4 times as many apples as Sally. Jonathan bought 6 more apples than Sally. How many apples did Jenny buy?

Alekssandra [29.7K]2 years ago

7 0

Word problem:

The sum of the present age of a father and his son is 60 years. Six year's ago, father's age was five times the age of the son. what will be the age of the son and father after 6 years?

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The polynomial function f(x)=-x^3+x^2+14x-24 has zeros at x=-4, x=3, and x=2. Which of the following graphs represents the funct

weqwewe [10]

Answer:

Assuming the choices are only of C and D, D would be the graph of the function.

Step-by-step explanation:

There are many things that would cause D to be the graph of f(x).

Firstly, D has the end behavior of a $-x^{3}$ function.

Secondly, it has correct zeroes

Lastly, Its y-intercept is -24, which is the case of the function f(x) as

$f(0) = -24$

6 0

2 years ago

3 lines are shown. A line with points M, H, K intersects with a line with points J, H, L at point H. Another line extends from p

otez555 [7]

Answer:

Option B.

Step-by-step explanation:

Given information: ∠MHL=(3x+20), ∠KHN=(x+25), and ∠JHN=(x+20).

We need to find the measure of ∠JHN.

$\angle MHL=\angle JHK$ (Vertical opposite angles)

$\angle MHL=\angle JHN+\angle KHN$

Substitute the given values.

$3x+20=(x+20)+(x+25)$

$3x+20=2x+45$

$3x-2x=45-20$

$x=25$

The value of x is 25. So, the measure of ∠JHN is

$\angle JHN=x+20=25+20=45$

The measure of ∠JHN is 45°.

Therefore, the correct option is B.

9 0

2 years ago

Read 2 more answers

The Dowers make pumpkin pie. If each person wants three slices of pie,and each pie is Cut into 9 slices, how many pies do they n

Anestetic [448]

Answer:

They need to make 5 pies for 15 people.

Step-by-step explanation:

15*3=45 slices of pie in total,

each pie is cut into 9 slices,

45/9=5 pies

5 0

2 years ago

Alonso went to the market with \$55$55dollar sign, 55 to buy eggs and sugar. He knows he needs a package of 121212 eggs that cos

Neko [114]

Answer: See explanation

Step-by-step explanation:

Based on the scenario in the question, the expression to calculate the number of boxes of sugar Alonso can buys will be:

= 2.75 + 11.50S ≤ 55

When solved further, this will be:

2.75 + 11.50S ≤ 55

11.50S ≤ 55 - 2.75

11.50S ≤ 52.25

S ≤ 52.25 / 11.50

S ≤ 4.54

He can buy 4 boxes of sugar

3 0

2 years ago

Mrs.Steﬀen’s third grade class has 30 students in it. The students are divided into three groups(numbered 1, 2,and 3),each havin

qaws [65]

Answer:

a. $\\ 10! = 3628800$ ;

b. $\\ 10!*10!*10! = 47784725839872000000 = 4.7784725839872*10^{19}$

Step-by-step explanation:

We need here to apply the Multiplication Principle or the Fundamental Principle of Counting for each answer. Answer b needs an extra reasoning for being completed.

The Multiplication Principle states that if there are n ways of doing something and m ways of doing another thing, then there are n x m ways of doing both (Rule of product (2020), in Wikipedia).

<h3>In how many ways can ten students line up? </h3>

There are ten students. When one is selected, there is no other way to select it again. So, no repetition is allowed.

Then, in the beginning, there are 10 possibilities for 10 students; when one is selected, there are nine possibilities left. When another is selected, eight possibilities are left to form the file, and so on.

Thus, we need to multiply the possibilities after each selection: that is why the Multiplication Principle is important here.

This could be expressed mathematically using n!:

$\\ n! = n * (n-1)! * (n-2)! *...* 2*1.$

For instance, $\\ 5! = 5 * (5-1)! * (5-2)! *...*2*1 = 5 * 4 * 3 * 2 * 1 = 120.$

So, for the case in question, the ten students can line up in:

$\\ 10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3628800$ ways to line up in a single file.

<h3>Second Question</h3>

For this question, we need to consider the former reasoning with extra consideration in mind.

The members of Group 1 can occupy only the following places in forming the file:

$\\ G1 = \{ 1, 4, 7, 10, 13, 16, 19, 22, 25, 28\}^{th}$ places.

The members of Group 2 only:

$\\ G2 = \{ 2, 5, 8, 11, 14, 17, 20, 23, 26, 29\}^{th}$ places.

And the members of Group 3, the following only ones:

$\\ G3 = \{ 3, 6, 9, 12, 15, 18, 21, 24, 27, 30\}^{th}$ places.

Well, having into account these possible places for each member of G1, G2 and G3, there are: 10! ways for lining up members of G1; 10! ways for lining up members of G2 and, also, 10! ways for lining up members of G3.

After using the Multiplication Principle, we have, thus:

$\\ 10! * 10! * 10! = 47784725839872000000 = 4.7784725839872 *10^{19}$ ways the students can line up to come in from recess.

3 0

2 years ago