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Ivahew [28]
2 years ago
11

(Java)Write a program that calculates and displays the conversion of an entered number of dollars into currency denominations—20

s, 10s, 5s, and 1s. Example output: $452 converted is 22 $20s, 1 $10s, 0 $5s, and 2 $1s.​
Computers and Technology
1 answer:
Nataly [62]2 years ago
8 0

Answer:

Below!

Explanation:

This is the code I have. I am not sure what I am missing that it won't accept -  

import java.util.Scanner;

class Dollars {

   public static void main(String[] args) {

            int numTwenties,numTens,numFives,numOnes,dollarAmount;  

       Scanner sc= new Scanner(System.in);

       System.out.println("Please enter a dollar amount: ");  

       dollarAmount = sc.nextInt();

        numTwenties = dollarAmount/20;

        numTens = (dollarAmount - 20*numTwenties)/10;

        numFives = (dollarAmount - (10*numTens + 20*numTwenties))/5;

        numOnes = (dollarAmount - (10*numTens + 20*numTwenties + 5*numFives));

       System.out.println(+ dollarAmount + " converted is" + numTwenties + " $20s, " + numTens + " $10s, " + numFives + " $5s, and " + numOnes + " $1s.");  

   }

}

This is what it is giving me -

Test CaseIncomplete

Dollars 598

Input598

OutputPlease enter a dollar amount: 598

598 converted is29 $20s, 1 $10s, 1 $5s, and 3 $1s.

Results

$598 converted is 29 $20s, 1 $10s, 1 $5s, and 3 $1s

Expected Output

$598 converted is 29 $20s, 1 $10s, 1 $5s, and 3 $1s

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Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

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int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

6 0
2 years ago
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