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zloy xaker [14]
2 years ago
9

Compare mechanical, chemical, and legislative control to the use of nonnative species as a control method.

Biology
1 answer:
just olya [345]2 years ago
3 0
Non native species are organisms that do not naturally occur in a given area. They may have been transferred either accidentally or deliberately from their place of origin to the new area through human activities.

Non native species may become invasive species if they cause harm to the economy, human health, or environment.

Control methods used to eliminate invasive species are:
1) mechanical - physically removing the invasive species or changing the habitat condition of the affected area.
2) chemical - using of pesticides, fungicides, or herbicides to kill off invasive species.
3) legislative - introducing the natural enemy of the invasive species. It may be a predator or parasite that is from its native range.
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Where are carbohydrates found in the body? And in cells?
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Hi,

Answer: The Liver

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Which part of an individual amino acid distinguishes it from other amino acids? which part of an individual amino acid distingui
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2 years ago
In the fruit fly, Drosophila melanogaster, a spineless (no wing bristles) female fly is mated to a male that is claret (dark eye
Korolek [52]

Explanation:

We have three genes in the same chromosome and are trying to determine their order and relative distance to each other.

<u>The genes and possible alleles are:</u>

  • claret (c/c+)
  • spineless (s/s+)
  • hairless (h/h+)

All mutations are recessive: two copies of the mutant allele are needed for the fly to show that trait.

<u>Parental cross</u>

  • claret hairless male:\frac{s^+\  c\ h}{s^+\  c \ h}
  • spineless female: \frac{s\  c^+\ h^+}{s\  c^+ \ h^+}

Each parent can produce 1 type of gamete only, so the F1 will be homogeneous:

<u>F1</u>

<u>\frac{\ s\  \ \  c^+\ \ h^+}{s^+\   \ c \ \ \ h}</u>

During meiosis, the F1 females can produce 8 types of gametes: 2 parentals and 6 recombinants (two of them, the result of a double crossing over).

If they are test crossed to homozygous recessive males (which can only produce a \frac{s  \ c\   h}{} gamete), the following phenotypes are obtained (I just write the alleles they inherited from the female fly, as the ones that came from the male are the same for all of them):

  • 321 spineless (s c+ h+) ----> Parental
  • 309 claret, hairless (s+ c h) ----> Parental
  • 130 claret, spineless (s c h+) ----> Recombinant
  • 140 hairless  (s+ c+ h) ----> Recombinant
  • 32 hairless, claret, spineless  (s c h) ----> Recombinant
  • 38 WT  (s+ c+ h+) ----> Recombinant
  • 18 claret (s+ c h+) ----> Double Recombinant
  • 12 hairless, spineless (s c+ h) ----> Double Recombinant

The phenotypes observed in the highest frequency are always the parentals, and the ones in the lowest frequency are always the double recombinants.

<u>To determine the order of the genes:</u>

  1. we have to write down the genotype of the F1 female three times, changing the order of the genes each time.
  2. Then, we hypothesize what the double recombinant gametes would look like.
  3. When the theoretical double recombinants we obtain are the same as the ones observed in the F2, we know that <em>that </em>is the correct order of the genes.

In this problem, only if the middle gene is h+/h the double crossing over gives us the observed double recombinant gametes, therefore <u>hairless</u> is the middle gene.

\frac{s\ h^+\ c^+}{s^+\  h\ c}

<u> Double recombinants:</u>

  • s h c+ ----> spineless hairless
  • s+  h+ c  ----> claret

<u>To determine the distance between the genes:</u>

Genetic distance (m.u.) = Recombination Frequency x 100

  • Distance between the spineless and hairless genes:

Distance \ [s-h]= \frac{number\ of\  recombinants \ [s-h]}{Total number of individuals}  * 100\\\\\\Distance \ [s-h]= \frac{32+38+12+18}{1000}  * 100\\\\Distance \ [s-h]= 10\  map\ units

  • Distance between the hairless and claret genes:

Distance \ [h-c]= \frac{130+140+12+18}{1000}  * 100\\\\Distance \ [h-c]= 30\  map\ units

<h3><u>The gene map for these genes is:</u></h3>

spineless -----------------hairless ---------------------------claret

                   10 m.u.                            30 m.u.

3 0
1 year ago
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